Query 6

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course Mth 151

Question: `qQuery 1.1.4 first 3 children male; conclusion next male. Inductive or deductive?

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Your solution:

Inductive

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Given Solution:

`a** The argument is inductive, because it attempts to argue from a pattern. **

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Self-critique (if necessary):

Got it right, but I didn’t explain the reason why I picked it. Sorry!!!!

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Question: `qQuery 1.1.8 all men mortal, Socrates a man, therefore Socrates mortal.

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Your solution:

Deductive, because the reasoning goes from general to specific.

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Given Solution:

`a** this argument is deductive--the conclusions follow inescapably from the premises.

'all men' is general; 'Socrates' is specific. This goes general to specific and is therefore deductive.

COMMON ERROR: because it is based on a fact, or concrete evidence.

Fact isn't the key; the key is logical inevitability. The argument could be 'all men are idiots, Socrates is an man, therefore Socrates is an idiot'. The argument is every bit as logical as before. The only test for correctness of an argument is that the conclusions follow from the premises. It's irrelevant to the logic whether the premises are in fact true. **

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Self-critique (if necessary):

Yeah for me, I got it right again!!!!!!

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Question: `qQuery 1.1.20 1 / 3, 3 / 5, 5/7, 7/9, ... Probable next element.

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Your solution:

You take the denominator and make it the numerator in the next element. Then you add the numerator by its self and take one away to get the new denominator. So the next element is as follows: 9/17, 17/33,…..

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Given Solution:

`a**The numbers 1, 3, 5, 7, 9 and 11 are odd numbers. We note that the numerators consist of the odd numbers, each in its turn. The denominator for any given fraction is the next odd number after the numerator.

Since the last member listed is 7/9, with numerator 7, the next member will have numerator 9; its denominator will be the next odd number 11, and the fraction will be 9/11.

There are other ways of seeing the pattern. We could see that we use every odd number in its turn, and that the numerator of one member is the denominator of the preceding member.

Alternatively we might simply note that the numerator and denominator of the next member are always 2 greater than the numerator and denominator of the present member. **

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Self-critique (if necessary):

I got the numerator right, but not the new denominator. I was adding and subtracting. But I see why it would be 11.

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Question: `qQuery 1.1.23 This problem wasn't assigned, but you should be able to make a good attempt: 1, 8, 27, 64, ... What is the probable next element?

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Your solution:

I am not sure or why it would be what it is. I know that 8 * 8 is 64, but the 27 is 9 *3, so I really not sure what the next element it would be.

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Given Solution:

`a** This is the sequence of cubes. 1^3 = 1, 2^3 = 8, 3^3 = 27, 4^3 = 64, 5^3 = 125.

The next element is 6^3 = 216.

Successive differences also work:

1 8 27 64 125 .. 216

7 19 37 61 .. 91

12 18 24 .. 30

6 6 .. 6 **

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Self-critique (if necessary):

With the eight I was thinking the numbers could be square, didn’t think about the numbers could be cubed.

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Question: `qQuery 1.1.36 11 * 11 = 121, 111 * 111 = 12321 1111 * 1111 = 1234321; next equation, verify.

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Your solution:

11111 * 11111 = 123,454,321

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Given Solution:

`a** We easily verify that 11111*11111=123,454,321 **

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Self-critique (if necessary):

Yup, that is what I got.

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Question: `qDo you think this sequence would continue in this manner forever? Why or why not?

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Your solution:

I believe that it can because of the fact the numbers are the same just adding more wouldn’t change the sequence.

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Given Solution:

`a** You could think forward to the next few products: What happens after you get 12345678987654321? Is there any reason to expect that the sequence could continue in the same manner?

The middle three digits in this example are 8, 9 and 8. The logical next step would have 9, 10, 9, but now you would have 9109 in the middle and the symmetry of the number would be destroyed. There is every reason to expect that the pattern would also be destroyed. **

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Self-critique (if necessary):

I can honestly say I don’t begin to understand what is being said in this given solution, sorry!!!!!

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Self-critique Rating:

@& You would have to continue the sequence for a few more steps to see how you get to 12345678987654321.*@

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Question: `qQuery 1.1.46 1 + 2 + 3 + ... + 2000 by Gauss' method

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Your solution:

2 + 1999, 3 + 1998

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Given Solution:

`a** Pair up the first and last, second and second to last, etc.. You'll thus pair up 1 and 2000, 2 and 1999, 3 and 1998, etc..

Each pair of numbers totals 2001.

Since there are 2000 numbers there are 1000 pairs. So the sum is 2001 * 1000 = 2,001,000 **

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Self-critique (if necessary):

I got the first part, but didn’t get the second part. Sorry I saw it in the book, but for some reason didn’t think I had to do it with this question. Sorry!!!!

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Question: `qQuery 1.1.57 142857 * 1, 2, 3, 4, 5, 6. What happens with 7? Give your solution to the problem as stated in the text.

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Your solution:

142857 * 7 = 999,999 – not sure what you need for this, but I would say the solution is that with 7 you get six number and they are all the same.

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Given Solution:

`a** Multiplying we get

142857*1=142857

142857*2= 285714

142857*3= 428571

142857*4=571428

142857*5= 714285

142857*6=857142.

Each of these results contains the same set of digits {1, 2, 4, 5, 7, 8} as the number 1428785. The digits just occur in different order in each product.

We might expect that this pattern continues if we multiply by 7, but 142875*7=999999, which breaks the pattern. **

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Self-critique (if necessary):

I understand the reason the answer is what it is, but I didn’t realize that in the answers to the first six they had the same number just didn’t order. I did realize that the seven did break the pattern, but I put it because all the numbers where the same.

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Question: `qQuery 1.1.57 142857 * 1, 2, 3, 4, 5, 6. What happens with 7? Give your solution to the problem as stated in the text.

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Your solution:

142857 * 7 = 999,999 – not sure what you need for this, but I would say the solution is that with 7 you get six number and they are all the same.

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Given Solution:

`a** Multiplying we get

142857*1=142857

142857*2= 285714

142857*3= 428571

142857*4=571428

142857*5= 714285

142857*6=857142.

Each of these results contains the same set of digits {1, 2, 4, 5, 7, 8} as the number 1428785. The digits just occur in different order in each product.

We might expect that this pattern continues if we multiply by 7, but 142875*7=999999, which breaks the pattern. **

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Self-critique (if necessary):

I understand the reason the answer is what it is, but I didn’t realize that in the answers to the first six they had the same number just didn’t order. I did realize that the seven did break the pattern, but I put it because all the numbers where the same.

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Self-critique Rating:

#*&!

&#This looks good. See my notes. Let me know if you have any questions. &#