Query 29

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course Mth 151

029. `query 29

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Question: `q7.3.18 (1/3) / 6 = 1/18. Is this ratio equation valid or not and how did you determine your answer?

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Your solution:

Yes this equation is valid. I am not quite sure how to get the answer. I plugged it into my calculator and give came up. I was thinking that you would do the following:

I think you would do the following 1/3 times by 6; 6 is actually 6/1; when you cross multiple which will give you 1/18…..

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Given Solution:

`a**If we multiply both sides by 6 * 18 we get

6 * 18 * (1/3 ) / 6 = 6 * 18 * (1 / 18) or

18 * 1/3 = 6. Note that the effect here is the same as that of 'cross-multiplying', but it's a good idea to remember that 'cross-multiplying' is really a shortcut way to think of multiplying both sides by the common denominator.

Since 18 * 1/3 = 18 / 3 = 6, the equation 18 * 1/3 = 6 is true, which verifies the original equality. **

@& Another way to calculate this:

(1/3) / 6 = (1/3) * (1/6) = 1 / 18.

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Self-critique (if necessary):

I think I got it right, not sure though…

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Question: `q7.3.20 z/8 = 49/56. Solve this proportionality for z.

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Your solution:

z = 7; I got this by cross multiplying giving you an equation of 56z = 392; then you would divide each side by 56.

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Given Solution:

`a**Multiply both sides by 8 * 56 to get

8 * 56 * z / 8 = 8 * 56 * 49 / 56. Simplify to get

56 * z = 8 * 49. Divide both sides by 56 to get

z = 8 * 49 / 56. Simplify to get

z = 7. **

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Self-critique (if necessary):

I got it right, and I think I did it the same way that you did…..

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Question: `q7.3.42 8 oz .45; 16 oz. .49; 50 oz. 1.59`sb Which is the best value per unit for green beans and how did you obtain your result?

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Your solution:

I believe what you would do is take each ounces and divided by the cost and it will give us what is cost per ounce and therefore telling us the best value per unit.

.45/8 = .056 per unit

.49/16 = .030 per unit

1.59/50 = .031 per unit

The best value is the 16 oz for .49….

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Given Solution:

`a** 45 cents / 8 oz = 5.63 cents / oz.

49 cents / 16 oz = 3.06 cents / oz.

159 cents / 50 oz = 3.18 cents / oz.

16 oz for .49 is the best value at 3.06 cents / oz. **

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Self-critique (if necessary):

I got it right!!!!

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Question: `q7.3.45 triangles 4/3, 2, x; 4, 6, 3. What is the value of x and how did you use an equation to find it?

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Your solution:

Even looking at the book I am not sure what to do. I understand that the 4/3 is to 4; 2 is to 6 and x is to 3. But from there I am not sure.

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Given Solution:

`a** the 4/3 corresponds to 4, 2 corresponds to 6, and x corresponds to 3.

The ratios of corresponding sides are all equal.

So 4/3 / 4 = 2 / 6 = x / 3.

Just using x / 3 = 2 / 6 we solve to get x = 1.

We would have obtained the same thing if we had used x / 3 = 4/3 / 4. **

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Self-critique (if necessary):

Darn it I had it right. But I didn’t do the x/3 - 4/3/4; If I would done that one and got the 1 again, I would have said that. I hate that I do this so often. I do understand what we are supposed to do and why….

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Question: `qIf z = 9 when x = 2/3 and z varies inversely as x, find z when x = 5/4. Show how you set up and used an equation of variation to solve this problem.

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Your solution:

I just don’t know what to do!!!! When looking what the a part of the solution and not looking further I got that the z = 4.8

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Given Solution:

`a** If z varies inversely as x then z = k / x.

Then we have

9 = k / ( 2/3). Multiplying both sides by 2/3 we get

2/3 * 9 = k so

k = 6.

Thus z = 6 / x. So when x = 5/4 we have

z = 6 / (5 /4 ) = 24 / 5 = 4.8. Note that the translations of other types of proportionality encountered in this chapter include:

z = k x^2: z varies as square of x.

z = k / x^2: z varies inversely as square of x.

z = k x: z is proportional to x. **

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Self-critique (if necessary):

I got this right; of course I cheated a little by seeing the first sentence in your given solution….

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Question: `q7.3.72. Illumination is inversely proportional to the square of the distance from the source. Illumination at 4 ft is 75 foot-candles. What is illumination at 9 feet?

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Your solution:

Once again, I just not sure what I need to do with this problem.

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Given Solution:

`a**Set up the variation equation I = k / r^2, where I stands for illumination and r for distance (you might have used different letters). This represents the inverse proportionality of illumination with the square of distance.

Use I = 75 when r = 4 to get

75 = k / 4^2, which gives you

k = 75 * 4^2 = 75 * 16 = 1200.

Now rewrite the proportionality with this value of k: I = 1200 / r^2.

To get the illumination at distance 9 substitute 9 for r to get

I = 1200 / 9^2 = 1200 / 81 = 14.8 approx..

The illumination at distance 9 is about 14.8.

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Self-critique (if necessary):

I got it why you did what you did, but this will be another chapter that is going to get me!!! Ugh!!

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Question: `q7.3.66 length inv prop width; L=27 if w=10; w = 18. L = ?

Explain how you set up and used a variation equation to obtain the length as a function of width, giving your value of k. Then explain how you used your equation to find the length for width 18

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Your solution:

L = 15; I got this by doing the following:

27 = k/10; times each side by 10;

270 = k;

18 = 270/L; times each side by L;

18L = 270; divide each side by 18

Giving me L = 15

confidence rating #$&*:

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Given Solution:

`a**Set up the variation equation L = k / w, which is the inverse proportion.

Use L = 27 when w = 10 to get

27 = k / 10, which gives you

k = 27 * 10 = 270.

Now we know that L = 270 / w.

So if w = 18 you get

L = 270 / 18 = 15. **

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Self-critique (if necessary):

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Question: `q7.3.66 length inv prop width; L=27 if w=10; w = 18. L = ?

Explain how you set up and used a variation equation to obtain the length as a function of width, giving your value of k. Then explain how you used your equation to find the length for width 18

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Your solution:

L = 15; I got this by doing the following:

27 = k/10; times each side by 10;

270 = k;

18 = 270/L; times each side by L;

18L = 270; divide each side by 18

Giving me L = 15

confidence rating #$&*:

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Given Solution:

`a**Set up the variation equation L = k / w, which is the inverse proportion.

Use L = 27 when w = 10 to get

27 = k / 10, which gives you

k = 27 * 10 = 270.

Now we know that L = 270 / w.

So if w = 18 you get

L = 270 / 18 = 15. **

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Self-critique (if necessary):

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Self-critique rating:

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@& You have a few errors but you did get that last one, and a couple of the others, so with practice you should be able to do fine on this test.*@