phy 121
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = 2m
`dt = .64 s
vAve = 2m / .64s
vAve = 3.125 m/s
aAve = `dv / `dt
aAve = 3.125m/s / .64s
aAve = 4.88 m/s^2
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
4.88 m/s^2 = `dv / 1.05s
4.88m/s^2 * 1.05s = `dv
`dv = 5.124 m
This is consistent.
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Yes, since the 4.88 is the average acceleration, if doubled it would be 9.8 m/s^2.
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20 min.
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