phy 121
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
The slope .05 is rise/run, the run would be 8 seconds, therefore rise is .4m/s
The slope .10, the run would be 8 seconds, therefore rise would be .8m/s
a = `dv / `dt
a = (.8m/s - .4m/s) / 8
a = .05m/s^2
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15 min.
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