#$&*
** Question Form_labelMessages **
can not access outlook
** **
** **
** **
I can not get into Outlook. I have tried my student user name and password even replaced the user name with my email to see if that would work, however I feel like I need something else to get into it,should i register for one?
@&
I'm not sure why you are trying to get into Outlook or what function it is (or should be) serving for you in this course.
You appear to have been using Web Outlook for your email.
What specifically is it you are trying to access?
*@
#$&*
Mth163
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
trapezoid june 8,3013 time 17
** **
Question: `q004. One straight line segment connects the points (3,5) and (7,9) while another connects the points (10,2) and (50,4). From each of the four points a line segment is drawn directly down to the x axis, forming two trapezoids. Which trapezoid has the greater area? Try to justify your answer with something more precise than, for example, 'from a sketch I can see that this one is much bigger so it must have the greater area'.
Your solution: Using ((base one+ base two)*height)/2 . After graphing my points I counted the units needed (I cannot remember of I am supposed to use the spaces or lines to count???),( (5+5)*3.5)/2=35/2=17.5 units^2 .I did the same to the larger trapezoid ((2+4)*40)=240/2=120 units^2. Therefore our trapezoid the greatest area is (10,2) and (50,4). Confidence Assessment: 1 Question: I got confused with the orientation of the trapezoid see how it was so stretched out, so have any tips for keeping things strait???
** **
((base one+ base two)*height)/2 I understand this and what& where the terms are i also understand how to graph the points and connect them to the x axis from where they already have the points. What i do not under stand is stated in the last/next box.
** **
After graphing my points I counted the units needed (I cannot remember of I am supposed to use the spaces or lines to count???)Question: I got confused with the orientation of the trapezoid seeing how it was so stretched out, do you have any tips for keeping things strait???
@&
For thesee trapezoid you could rely on a sketch of each. Sketches are indispensible for keeping situations of this nature straight.
A comparison of the dimensions of the two trapezoids suffices to prove that the second has the greater area.
Sketched on a set of coordinate axes you can quickly conclude that the second has a left-to-right width of 40, compared to the width 4 of the first, so that the second has 10 times the width. The only way for the first to have more area would be for it to extend 10 times as high above the x axis, on the average. However the maximum height of the first is 9, which is less than 10 times the minimum height of the second.
*@
#$&*
Mth163
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
Mth163 2013 summer timeline
** **
The problem is i can only find the spring time of 2012 timeline for precal here is the link https://learn.vccs.edu/webapps/portal/frameset.jsp?tab_tab_group_id=_2_1&url=%2Fwebapps%2Fblackboard%2Fexecute%2Flauncher%3Ftype%3DCourse%26id%3D_598955_1%26url%3D
** **
I have read the only one on your site, which say spring 2012 and only has spring time dates. Do you want the summer 2013 assignments done in that order and what are the dates?
** **
Where is the summer 2013 time line Mth163 precal assignments and due dates sheet?
@&
Let me know, if you can, how you located the Spring dates.
The Summer dates are there on the course homepage under the menu link entitled "Due Dates".
The link you provided is a Blackboard link. The course homepage is not in Blackboard nor is it associated with Blackboard.
*@
@&
Reviewing your portfolio page I might see the reason for your apparent confusion.
The first seven document of the Initial Activities are the following:
A1. Preliminary Q-A-Self_Critique
A2. Introductory question_answer
A3. Homepage, due dates, course of study_163
A4. Understanding learning_objectives
A5. Using your DVDs
A6. More about communication
A7. How to succeed in your course
Your work on all of these is posted, with the exception of A3 and A4.
A3 is the exercise that introduces you to your homepage, due dates, etc..
You should go back and work through A3 and A4.
*@
@&
Reviewing your portfolio page I might see the reason for your apparent confusion.
The first seven document of the Initial Activities are the following:
A1. Preliminary Q-A-Self_Critique
A2. Introductory question_answer
A3. Homepage, due dates, course of study_163
A4. Understanding learning_objectives
A5. Using your DVDs
A6. More about communication
A7. How to succeed in your course
Your work on all of these is posted, with the exception of A3 and A4.
A3 is the exercise that introduces you to your homepage, due dates, etc..
You should go back and work through A3 and A4.
*@
#$&*
Mth163
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
think of a strategy 8june2013
** **
Question: `q006. If the population of the frogs in your frog pond increased by 10% each month, starting with an initial population of 20 frogs, then how many frogs would you have at the end of each of the first three months (you can count fractional frogs, even if it doesn't appear to you to make sense)? Can you think of a strategy that would allow you to calculate the number of frogs after 300 months (according to this model, which probably wouldn't be valid for that long) without having to do at least 300 calculations?
Your solution:
After 3 months your increase of frogs would be 26.26, Month 1,.1*20=2 then 20+2=22, M2, .1*22=2.2 then 22+2.2=24.2, M3 .1*24.2=2.42, 2.42+24.2=26.62. while trying to find a common difference between the populations of the first 3 months I found that it is increasing by .2 from the last increase, so in-between 22 and 24.2 it increases by 2.2 and between 24.2 and 26.62 the increase is 2.4 to confirm that the increases were increasing by .2 each time I found the 3rd month I added 2.6+26.62=29.22, I also did it the first way (to make sure) .1*26.62=2.662 then 26.62+2.662=29.282 ( it was a pretty close match but not perfect, still best I had so far.) With a common difference of my differences I apply it to a z score z=(x-mean)/standard deviation z=(300-2.2)/.1=2978 Knowing this may be terribly wrong I do not like to give up on things without trying.
** **
I understand everything else even how to apply the 1.1 but i dont fully understand how you got the 1.1
** **
Question: can you explain this part a little more as how you got 1.1 exactly???”The key to extending the strategy is to notice that multiplying a number by .1 and adding it to the number is really the same as simply multiplying the number by 1.1.”
@&
It would have been best to include the given solution so I can see the exact wording to which you had access. This would have the advantage that you could be sure I would phrase the explanation somewhat differently, hopefully in a way that would complement the given explanation.
*@
@&
I think the explanation below is worded differently than that in the given solution. I'm not sure how well it complements that explanation, not having that explanation at hand, but hopefully this will help.
*@
@&
Each year the population increases by 10% over its previous value.
So the new population would be equal to the previous value, plus 10% of the previous value.
Thus the new population would be 100% of the previous, plus 10% of the previous. THis would be 110% of the previous population.
110% is 1.1. So the new population is 1.1 times the previous.
*@
#$&*
Mth163
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
confused 8june2013 18:52
** **
Question:
Suppose you invest $1000 and, at the end of any given year, 10% is added to the amount. How much would you have after 1, 2
and 3 years?
What is an expression for the amount you would have after 40 years (give an expression that could easily be evaluated using a calculator, but don't bother to actually evaluate it)?
What is an expression for the amount you would have after t years?
Your solution:
After 3 years 1.1*1000=1,100(year 1) 1.1*1100=1,210(year2) 1.1*1210=1,331(year 3). 1.1*40 I am not sure what you are referring to when you say t years???
** **
everything else except What is an expression for the amount you would have after t years?
** **
I am not sure what you are referring to when you say t years???
@&
t is the symbol that stands for the number of year.
t would be regarded as a variable.
The 40-year factor would be 1.1^40.
The 100-year factor would be 1.1^100.
The t-year factor would be 1.1^t.
*@