#$&*
course Mth163
Question: If you make $50 in 5 hr, then at what rate are you earning money?
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Your solution:
$10 per hour. 50/5=10.
confidence rating #$&*: 3
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Self-critique Rating: OK
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Question: `q003.If you make $60,000 per year then how much do you make per month?
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Your solution:
$60,000/12=$5,000/month
confidence rating #$&*: 3
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Self-critique Rating: OK
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Question: `q004. Suppose that the $60,000 is made in a year by a small business. Would be more appropriate to say that the business makes $5000 per month, or that the business makes an average of $5000 per month?
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Your solution:
the business makes an average of $5000 per month
confidence rating #$&*: 3
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Self-critique Rating: OK
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Question: `q005. If you travel 300 miles in 6 hours, at what average rate are you covering distance, and why do we say average rate instead of just plain rate?
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Your solution:
300/6= 50mph average rate is not precise per actual mile it is combined data to guess what the ideal over average time spent on something would be. It’s like slope you could draw this on a graph to find 50 mph as well.
confidence rating #$&*: 3
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Self-critique Rating: OK
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Question: `q006. If you use 60 gallons of gasoline on a 1200 mile trip, then at what average rate are you using gasoline, with respect to miles traveled?
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Your solution:
1200/60= 20 gallons per mile, this feels off…
confidence rating #$&*: 1
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Self-critique (if necessary): duh moment.. 60/1200=.05 gallons per mile I just want to live in a world with Whole numbers I guess.
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Self-critique Rating:OK
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Question: `q007. The word 'average' generally connotes something like adding two quantities and dividing by 2, or adding several quantities and dividing by the number of quantities we added. Why is it that we are calculating average rates but we aren't adding anything?
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Your solution:
These rates have already been added form something else in an invisible subset that’s not really necessary to know what to do.
confidence rating #$&*: 3
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Self-critique Rating: OK
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Question: `q008. In a study of how lifting strength is influenced by various ways of training, a study group was divided into 2 subgroups of equally matched individuals. The first group did 10 pushups per day for a year and the second group did 50 pushups per day for year. At the end of the year to lifting strength of the first group averaged 147 pounds, while that of the second group averaged 162 pounds. At what average rate did lifting strength increase per daily pushup?
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Your solution:
365/147=2.48299 strength increased by day. 365/162=2.25309 strength increased by day.
confidence rating #$&*: 1
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Self-critique (if necessary):
So group 2 did 40 more push-ups per day then group 1, 50-10=40. The second group’s average lifting strength minus the first group’s average lifting strength will give you how much more lifting strength the second group had compared to the first which is 15 more pounds of lifting strength.
Self-critique Rating: 3
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Question: `q009. In another part of the study, participants all did 30 pushups per day, but one group did pushups with a 10-pound weight on their shoulders while the other used a 30-pound weight. At the end of the study, the first group had an average lifting strength of 171 pounds, while the second had an average lifting strength of 188 pounds. At what average rate did lifting strength increase with respect to the added shoulder weight?
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Your solution:
188-171= 17 average lifting strength difference (group 2 has 17lbs more of lifting strength than group 1) 30-10=20 the second group was practicing with 20 more pounds on their backs than group 1.
confidence rating #$&*:: 3
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Self-critique (if necessary): 17 lbs lifting/ 20 lbs added= .85 lbs added to lifting rate gives us the average rate at which strength increases compared to the added weight.
Self-critique Rating: 3
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Question: `q010. During a race, a runner passes the 100-meter mark 12 seconds after the start and the 200-meter mark 22 seconds after the start. At what average rate was the runner covering distance between those two positions?
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Your solution:
22/12=11/6=1.83, 12-1.83= that she ran between the 100 meter mark and the 200 meter mark in 10.17 seconds! And she is a very excellent runner.
@&
The second hundred in 10 seconds would be impressive.
*@
confidence rating #$&*:: 3
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Self-critique Rating: OK
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Question: `q011. During a race, a runner passes the 100-meter mark moving at 10 meters / second, and the 200-meter mark moving at 9 meters / second. What is your best estimate of how long it takes the runner to cover the intervening 100 meter distance?
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Your solution:
10 meters per second
confidence rating #$&*: 3
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Self-critique Rating: OK
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Self-critique (if necessary): 100 meters = 10 seconds ( travel time) so average speed is 10m/s to 9 m/s, (10 m/s + 9 m/s)/2=9.5 meters per second using this as our average rate the time to travel 100 meters would be divided by the average rate which is now 9.5, so 100 meters/ 9.5 m/s= 10.5 meters/sec
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Self-critique rating: 3
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Question: `q012. We just averaged two quantities, adding them and dividing by 2, to find an average rate. We didn't do that before. Why we do it now?
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Your solution:
Before we were not trying to find multiple things and what we were trying to find we already had all the elements we needed, but this is not the case for the previous problem. We did not know all the elements of that data set and in order to find them we had to work with what we had.
confidence rating #$&*: 2
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Self-critique (if necessary): In the other problems they were quantities not rate. While here we given two rates, in which we needed an average to solve.
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Self-critique rating: 2
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Question: `q013. The volume of water in a container increases from 1400 cm^3 to 1600 cm^3 as the depth of the water in the container changes from 10 cm to 14 cm. At what average rate was the volume changing with respect to depth?
Optional question: What does this rate tell us about the container?
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Your solution:
1600-1400= 200 cm^3 is the depth at which to liquid’s volume increases, while 4 cm is how high the liquid rose form the original 10 cm marker. 200 m^3/4 cm= 50 increased volume per centimeter. The rate tells us that the container if we start off dividing the volume by its height which at this current moment is 1600/14=114.268= L*W
confidence rating #$&*: 2
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Question: `q014. An athlete's rate of doing work increases more or less steadily from 340 Joules / second to 420 Joules / second during a 6-minute event. How many Joules of work did she do during this time?
Your solution:
(340 J / s + 420 J / s)/6m= 760/6=380/3=126.67 J/m. She would have done 760 Joules of work in 6 minutes.
@&
Good, but that's what she would have done in 2 seconds.
*@
confidence rating #$&*: 3
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