If your solution to stated problem does not match the given solution, you should self-critique per instructions at
http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm
.
Your solution, attempt at solution.
If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.
013. `query 13
Question:
`q query problem
2.3.40; was 2.3.37 .
Which graph matches the graph of the bus and why?
Your solution:
Confidence Assessment:
Given Solution:
** The bus only makes periodic stops, whereas the graph
for III only comes to a stop once. I
would matche the bus with II. **
Self-critique (if necessary):
Self-critique Rating:
Question:
`q describe the graph of the car with no traffic and no lights
Your solution:
Confidence Assessment:
Given Solution:
** The car matches up with (I), which is a continuous,
straight horizontal line representing the constant velocity of a car with no
traffic and no lights. *&*&
Self-critique (if necessary):
Self-critique Rating:
Question:
`q describe the graph of the car with heavy traffic
Your solution:
Confidence Assessment:
Given Solution:
** The car in heavy traffic would do a lot of speeding up
and slowing down at irregular intervals, which would match the graph in III
with its frequent increases and decreases. **
Self-critique (if necessary):
Self-critique Rating:
Question:
`q query2.4.6. 6th; 2.4.11
5th, 2.4.10 4th; 2.5.10 (was
2.4.8) q = f(p) (price and quantity
sold)what is the meaning of f(150) = 2000?
Your solution:
Confidence Assessment:
Given Solution:
*&*& q = 2000 when p = 150, meaning that when the
price is set at $150 we expect to sell 2000 units. *&*&
Self-critique (if necessary):
Self-critique Rating:
Question:
`q what is the meaning of f'(150) = -25?
Your solution:
Confidence Assessment:
Given Solution:
** f' is the derivative, the limiting value of `df / `dp,
giving the rate at which the quantity q changes with respect to price p.
If f'(150) = -25, this means that when the price is $150 the
quantity will be changing at a rate of -25 units per dollar of price
increase.
Roughly speaking, a one dollar price increase would result
in a loss of 25 in the number sold. **
Self-critique (if necessary):
Self-critique Rating:
Question:
`q query problem
2.4.26 6th;
2.4.23 5th; 2.4.18 4th; 2.4.7
graph of v vs. t for no parachute.
Describe your graph, including all intercepts, asymptotes,
intervals of increasing behavior, behavior for large |t| and concavity, and
tell why the graph's concavity is as you indicate.
Your solution:
Confidence Assessment:
Given Solution:
** When you fall without a parachute v will increase, most
rapidly at first, then less and less rapidly as air resistance increases.
When t = 0 we presume that v = 0.
The graph of v vs. t is therefore characterized as an increasing
graph beginning out at the origin, starting out nearly linear (the initial
slope is equal to the acceleration of gravity) but with a decreasing
slope. The graph is therefore concave
downward.
At a certain velocity the force of air resistance is equal
and opposite to that of gravity and you stop accelerating; velocity will
approach that 'terminal velocity' as a horizontal asymptote.
The reason for the concavity is that velocity increases less
and less quickly as air resistance increases; the approach of the velocity to
terminal velocity is more and more gradual **
Self-critique (if necessary):
Self-critique Rating:
Question:
`q What does the t = 0 acceleration indicate?
Your solution:
Confidence Assessment:
Given Solution:
** t = 0 acceleration is acceleration under the force of
gravity, before you build velocity and start encountering significant air
resistance.
Acceleration is rate of velocity change, indicated by the slope of the v vs. t graph. **
STUDENT QUESTION
I understand how acceleration and vel. are related, just not the first part of solution
INSTRUCTOR RESPONSE
If it wasn't for air resistance, acceleration would be equal
to that of gravity.
When you first jump out you aren't falling very fast, so there isn't much air
resistance to counter the acceleration of gravity, so you accelerate pretty much
at the acceleration of gravity.
You quickly speed up, and air resistance becomes more and more significant. So
your acceleration becomes less than the acceleration of gravity.
Assuming the ground is far away, this continues until air resistance is
effectively equal to the force of gravity, at which point your acceleration will
be zero. You will be at terminal velocity.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q Query Add comments
on any surprises or insights you experienced as a result of this assignment.
Self-critique (if necessary):
Self-critique Rating: