Phy 201
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
answer/question/discussion: average velocity = displacement/ time elapsed so average velocity is 30cm/5sec=6cm/sec
If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: I dont really know this answer but I think that the average velocity plus the initial velocity would be the final velocity so 6 + 0 = 6cm/sec
the ave velocity would be between the initial and final velocities, so final velocity couldn't be ave velocity + initial velocity
however you're on the right track in your overall approach
By how much did its velocity therefore change?
answer/question/discussion: The velocity did not change
you claim different initial and final velocities, and this constitutes a change in velocity
At what average rate did its velocity change with respect to clock time?
answer/question/discussion: it stayed the same.
What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: it would be a straight line because it is constant speed it would rise up to the 30 cm mark on the y axis and it would go to the left on the x axis to the 5 sec mark.
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30 min
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You need to carefully apply the definitions of average velocity and average acceleration.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#