random_assgn_3

course Phy 201

What are the acceleration and final velocity of an object whose average velocity, accelerating uniformly from rest for 7.9 seconds, is 59 cm/s? How far does the object travel during the 7.9 seconds? Average acceleration = change of velocity/ time elapsed so acceleration = 59 cm/7.9sec = 7.468 cm/sec

And the final velocity would be 59 + 7.468 = 66.468 cm/sec.

And the distance traveled = time * average speed so distance traveled = 7.9 * 7.468 = 58.997 cm.