course Mth 151
March 28 around 1:00
Mary Sholesassignment19-QUERY
q4.2.6:
This number expanded would look like this: (5*10^4)+(3*0^3)+(8*10^2)+(1*10^1)+(2*10^0)
*2 on confidence scale
q4.2.20:
5*10^2 + 3*10^1 + 6*10^0 + 2*10^2 + 7*10^1 + 9*10^0 = 7*10^2 + 10*10^1 + 15*10^0 which equals to the number 715 due to the extra steps by adding the notations.
*1
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