course Mth 151
April 11 around 3
Mary Sholes
assignment 23-QUERY
q5.1.18:
The factors would be 1,2,4,43,86,172
*3
q5.1.21:
25025 is not divisible by 2 because it doesn't end in an even number.
it isn't divisible by 3 because the sum 2 + 5 + 0 + 2 + 5 = 14 of its digits is not divisible by 3.
it isn't divisible by 4 because its last two digits do not form a number divisible by 4.
it is divisible by 5 because its last digit is 5.
it isn't divisible by 6 because it isn't divisible by 2 and 3.
it isn't divisible by 8 because its last three digits do not form a number divisible by 8.
it isn't divisible by 9 because the sum 2 + 5 + 0 + 2 + 5 = 14 of its digits is not divisible by 9.
it isn't divisible by 12 because it isn't divisible by both 3 and 4.
*2
q5.1.33:
we would keep dividing down by the prime numbers it divides by and see how many we have of that number. the final prime factorization would look like this: 2*2*2*3*3*5 or 2^3*3^2*5
*3
q5.1.60:
I didn't understand this at first, but when i looked at the given solution i understood and now know how to get that answer. you would take the prime factorization and break it down to with the powers. so you would have (4+1)*(4+1)*(2+1) to get 5*5*3=75.
*2
q5.1.80:
i don't understand how you would test this problem out?
You need to submit the entire document, including everything in that document, with your responses inserted at the specified places.
It's clear from your answers that you're doing OK, but in order for me to comment further I need to see everything.