Phy 231
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
The velocity will be 36 cm/s based on the kinematic equation Vf = 12 + 8t.
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
It's average velocity will be the mean between the final velocity (36) and initial velocity (12). This averages to 24 cm/s.
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• How far will it travel during this interval?
It will travel 72cm during this interval. This is found by taking the integral of the velocity function. This gives S(t) = 12t + 4t^2. If you solve the equation for t=3, you get 72 cm. The distance traveled can also be calculated by using the average speed. Since it traveled 24 cm/s for 3 seconds, 24*3 = 72.
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25 min
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