Phy 231
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
Velocity of the ball after one second would be 15 m/s.
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• What will be its velocity at the end of two seconds?
After two seconds, the ball's velocity would be 5 m/s.
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• During the first two seconds, what therefore is its average velocity?
During two seconds, its average velocity is 15 m/s.
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• How far does it therefore rise in the first two seconds?
It therefore travels 30 meters in two seconds.
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
At three seconds, its velocity will be -5 m/s. At four seconds, its velocity will be -15 m/s.
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
The ball reaches its maximum height at 2.5 seconds. It has risen 31.25 meters at that instant.
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
Its average velocity for the first four seconds is 5 m/s. It will be at height 20 meters at this time.
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• How high will it be at the end of the sixth second?
The ball will be at ground level by this time.
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25 minutes
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