Phy 231
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
If the direction of 120 degrees is the direction of motion, then the force at 270 degrees would be considered 'backwards'. Since 270 degrees is straight downwards, down and left are usually considered negative while up and right are considered positive. I say this force opposes motion.
• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
Without magnitudes of these forces, you cannot tell the after-collision velocity. But since the force opposes the motion of the vector, I would assume that the object would slow down.
• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
Since 120 degrees, the direction of motion, is up and to the left, the component that would be perpendicular to this will run up and to the right.
• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
Depending on the magnitudes involved, the object should veer to the left.
• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
I don't understand how you can tell which is greater, since no magnitudes are give, just angles.
An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
If the direction of 120 degrees is the direction of motion, then the force at 270 degrees would be considered 'backwards'. Since 270 degrees is straight downwards, down and left are usually considered negative while up and right are considered positive. I say this force opposes motion.
• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
Without magnitudes of these forces, you cannot tell the after-collision velocity. But since the force opposes the motion of the vector, I would assume that the object would slow down.
• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
Since 120 degrees, the direction of motion, is up and to the left, the component that would be perpendicular to this will run up and to the right.
• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
Depending on the magnitudes involved, the object should veer to the left.
• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
I don't understand how you can tell which is greater, since no magnitudes are give, just angles.
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15 min
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Good.
However note that you can determine which is greater, and the answer does not depend on the magnitudes, only on the directions. Check the link. You'll understand.
&#Please compare your solutions with the expanded discussion at the link
Solution
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