Randomized Problem 13

course PHY 201

Dear Prof. Smith,Here is my Randomized Problem version 13 fro assignment 3.

Thanks

Assignment 3

Version 13

An object travels a distance of 32 cm in 17.6 seconds from start to finish. If its acceleration is uniform and its initial velocity zero, then what are its average velocity, acceleration and final velocity?

X0 = 0 cm

X1 = 32 cm = 0.32 m

T0 = 0 sec

T1 = 17.6 sec

V0 = 0 m /sec

a) average velocity = displacement / time elapsed

vAve = ‘ds / ‘dt

‘ds = x1 – x0 = 0.32 – 0 = 0.32 m

‘dt = 17.6 – 0 = 17.6 sec

vAve = 0.32 / 17.6 = 0.01818182 m/sec

b) acceleration = change of velocity / time elapsed

acceAve = vAve / ‘dt

Average acceleration is change in velocity / change in clock time, not average velocity / change in clock time.

acceAve = 0.01818182 / 17.6 = 0.0010331 m/sec^2

.01818... m/s is your average velocity, not the change in velocity.

You obtain the correct final velocity below. The initial velocity is 0. What therefore is the change in velocity, and what is the acceleration?

c) vAve = (V0 + V1) / 2

final velocity = V1 = 2 * vAve – V0

V1 = 2 * 0.01818182 – 0 = 0.03636364 m/sec

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See my notes and please submit either a revision or, if necessary, questions.