course Phy 201
Hello Prof. Smith,Here is my Revision for Randomized problem 13. It is on the bottom.
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Tanya" "Randomized Problem 13
course PHY 201
Dear Prof. Smith,
Here is my Randomized Problem version 13 fro assignment 3.
Thanks
Assignment 3
Version 13
An object travels a distance of 32 cm in 17.6 seconds from start to finish. If its acceleration is uniform and its initial velocity zero, then what are its average velocity, acceleration and final velocity?
X0 = 0 cm
X1 = 32 cm = 0.32 m
T0 = 0 sec
T1 = 17.6 sec
V0 = 0 m /sec
a) average velocity = displacement / time elapsed
vAve = ‘ds / ‘dt
‘ds = x1 – x0 = 0.32 – 0 = 0.32 m
‘dt = 17.6 – 0 = 17.6 sec
vAve = 0.32 / 17.6 = 0.01818182 m/sec
b) acceleration = change of velocity / time elapsed
acceAve = vAve / ‘dt
Average acceleration is change in velocity / change in clock time, not average velocity / change in clock time.
acceAve = 0.01818182 / 17.6 = 0.0010331 m/sec^2
.01818... m/s is your average velocity, not the change in velocity.
You obtain the correct final velocity below. The initial velocity is 0. What therefore is the change in velocity, and what is the acceleration?
c) vAve = (V0 + V1) / 2
final velocity = V1 = 2 * vAve – V0
V1 = 2 * 0.01818182 – 0 = 0.03636364 m/sec
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See my notes and please submit either a revision or, if necessary, questions.
Revision
An object travels a distance of 32 cm in 17.6 seconds from start to finish. If its acceleration is uniform and its initial velocity zero, then what are its average velocity, acceleration and final velocity?
X0 = 0 cm
X1 = 32 cm = 0.32 m
T0 = 0 sec
T1 = 17.6 sec
V0 = 0 m /sec
• Average acceleration = change in velocity / change in clock time = ‘dv / ‘dt
average velocity = (change in velocity) / (change in clock time)
change in velocity = average velocity * change in clock time = 0.01818182 m/sec * (17.6 - 0) = 0.001033 m /sec
aAve = 0.001033 m /sec / 17.6 sec = 0.0000587 m /sec^2
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