Vectors

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course MTH 177

9/2 4:00 PM

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/

file3_259.htm

.

Your solution, attempt at solution. If you are unable to attempt a solution,

give a phrase-by-phrase interpretation of the problem along with a statement of

what you do or do not understand about it. This response should be given, based

on the work you did in completing the assignment, before you look at the given

solution.

009. Vectors

Goals for this Assignment include but are not limited to the following:

1. Given the magnitude and direction of a vector determine its components.

2. Given the components of a vector determine its magnitude and direction.

3. Given two or more vectors determine the magnitude and angle of their sum.

Click once more on Next Question/Answer for a note on Previous Assignments.

Previous Assignments: Be sure you have completed Assignment 8 as instructed

under the Assts link on the homepage and submitted the result of the Query and

q_a_ from that Assignment.

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Question: `q001. Sketch the points (2,3) and (9,14) on a set of coordinate

axes. Give the x and the y displacements from (2,3) to (9,14).

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Your solution:

using x2-x1 and y2-y1 we get the following answers:

x displacement is 9-2=7

y displacement is 14-3=11

confidence rating #$&*: 3

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Given Solution:

`aAs shown in Figure 75, the x displacement is from 2 to 9, a displacement of 9

- 2 = 7, while the y displacement is from 3 to 14, a displacement of 14 - 3 =

11. The arrows represent the direction of the displacements, from the initial

point (2, 3) to the terminal point (9, 14).

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Self-critique (if necessary):ok

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Self-critique Rating:

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Question: `q002. In the preceding example we saw that the x and y displacement

from from (2,3) to (9,14) are 9-2 = 7 and 14-3 = 11. Sketch an arrow which

originates at (2,3) and terminates at (9,14), with the point of the arrow at the

terminating end. If we were to sketch a geometrically similar arrow, having the

same slope, orientation and length as the preceding, but starting at the point

(-2, 5) at what point would the arrow terminate? Note that we can and should

really incorporate information from the physics introductory problems.

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Your solution:

since -2+7=5 and 5+11=17

It would terminate at (5,16)

confidence rating #$&*: 3

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Given Solution:

`aOriginating at (-2,5) the arrow will displace 7 units in the x direction and

11 units in the y direction. Starting at x = -2 the arrow will displace 7 units

in the x direction to end up at x = -2 + 7 = 5. Starting at y = 5 the arrow will

displace 11 units in the y direction and end up at y = 5 + 11 = 16. The arrow

therefore originates at (2,-5) and terminates at (5, 16).

If we sketch the same arrow starting from the point (-2, 5) then it will again

displace 7 units in the x direction, ending up at x = -2 + 7 = 5, and 11 units

in the y direction, ending up at y = 5 + 11 = 16. As shown in Figure 58 the

arrow terminates at the point (5, 16).

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question: `q003. We say that the displacement of 7 units in the x direction

and 11 units in the y direction is a vector, represented by the arrows used in

the preceding problems and denoted using 'pointy braces' as < 7, 11 >. If we

apply this vector, starting this time at the origin, at what point do we end up?

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Your solution:

since 0+7=7 and 0+11=11

If you start at the origin (0,0) the vector terminates at point (7,11)

confidence rating #$&*: 3

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Given Solution:

As shown in Figure 40 this vector takes us from the origin (0,0) to the point

(7, 11).

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Self-critique (if necessary):OK

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Self-critique Rating:3

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Question: `q004. If we start from the terminal point of the vector in the

preceding exercise and sketch a new vector having x displacement 3 and y

displacement -8, at what point do we end up? Sketch the arrows representing

these two vectors, the first running from (0,0) to (7,11) and the second from

that point to its terminal point.

Now sketch a vector from directly from (0,0) to the terminal point of the second

vector.

How can the x displacement of this new vector be calculated from the x

displacements of the first two vectors? Answer the same question for the y

coordinates.

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Your solution:

starting at point (7,11) you would go right 3 and go down 8

since 7+3=10 and 11-8=3

the new vector would go from (7,11) to (10,3)

confidence rating #$&*:3

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Given Solution:

`aAs shown in figure 11, the second vector runs from (7, 11) to (7 + 3, 11 + (-

8) ) = (10, 3).

The vector from the initial point of the first vector to the terminal point of

the second therefore runs from (0, 0) to (10, 3), as shown in Figure 72.

It should be clear from the calculations done above and from the sketches that

the x displacement of the new vector is calculated by adding the x displacements

of the original two vectors, and that the same strategy works for the y

displacements.

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question: `q005. In what sense can we say that the vector <10,3> is the sum of

the two vectors <7, 11> and <3, -8>?

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Your solution:

if you add the x coordinates 7 and 3 you get 10

if you add the y coordinates 11 and -8 you get 3

these are the sums of the vectors

confidence rating #$&*: 3

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Given Solution:

`aThe x coordinate of the new vector to is 10, which is the sum 7 + 3 of the x

coordinates of the two vectors. The y coordinate of the new vector is 3, the sum

11 + (-8) of the y coordinate of the two vectors. In this respect it is the sum.

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question: `q006. Access the site

http://vhmthphy.vhcc.edu/ph1introsets/default.htm

and choose Set 5, Vectors. Click in turn on Problems 1 - 9 and see if you can

solve these problems. Solutions are given and are generalized and many are

accompanied by figures. If you can't immediately solve them, study the

solutions and learn to solve them. Explain the solution to the first problem.

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Your solution:

To solve problem one you need to multiply the magnitude of 9 by the vector

velocity of the x (cos) and y (sin) axis of 50 deg.

This would be 9cos(50 deg) for the x value velocity which is 5.78

and 9sin(50deg) for the y value velocity which is 6.89

confidence rating #$&*: 3

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Given Solution:

`aIn case clarification is needed, displacement is just movement through a

distance and in a certain direction. The vector (3, -8) of the preceding

problem (and figur 72) corresponds to a displacement of 3 units in the x

direction and -8 units in the y direction.

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Your solution: OK

confidence rating #$&*: 3

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Given Solution:

`aThis completes this q_a_. Click once more for a message on completing the

remainder of this assignment.

Complete Assignment 9, including Class Notes, text problems and Web-based

problems as specified on the Assts page.

When you have completed the entire assignment run the Query program. Submit

SEND files from Query and q_a_.

end program

001. Radian measure and the unit circle.

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Your solution:

Ok

confidence rating #$&*:

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Given Solution:

`aGoals for this Assignment include but are not limited to the following:

1. Know the definition of the radian.

2. Relate coordinate positions on the unit circle to angular displacement and

to arc displacement.

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Self-critique (if necessary):ok

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Self-critique Rating:3

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