query_09_1

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course Mth 277

9/9/12 11pm

If your solution to stated problem does not match the given solution, you should self-critique per instructions athttp://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

At the end of this document, after the qa problems (which provide you with questions and solutions), there is a series of Questions, Problems and Exercises.

query_09_1

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Question: Sketch the vector from P to Q, write it into standard component form, and find ||PQ||. P=(4,-1) Q=(-3,7).

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Your solution:

(-3-4)i + (7+1)j. -7i +8j.

sqrt( 7^2 + 8^2) = sqrt(113).

confidence rating #$&*:

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Given Solution:

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Self-critique (if necessary):

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Self-critique rating:

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Question: Let u = <-4,3> and v = <2,-1/2>. Find scalars s and t so that s * <0,3> + tu = v.

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Your solution:

s3j -4t i +3tj = 2i - .5j.

-4t i = 2i. t = -.5

3s +3t = -.5

3s + 3(-.5) = -.5.

3s = 1. s= 1/3.

t= -1/2

s=1/3

confidence rating #$&*:

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Given Solution:

The equation

s * <0,3> + tu = v

becomes

s * <0, 3> + t * <-4, 3 > = < 2, -1 / 2 >

or

<0, 3s > + <-4 t, 3 t > = <2, -1/2 >.

and finally

<0 - 4 t, 3 s + 3 t > = < 2, -1/2 >.

Since the two vectors are equal if an only if their two components are equal, this is equivalent to the two simultaneous equations

-4 t = 2

3 s + 3 t = -1/2.

The solution of these equations is

t = -1/2, s = 1/3.

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Self-critique (if necessary): OK

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Self-critique rating: OK

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Question: Let u = 4i - 3j, v = -3i + 4j , and w = 6i - 3j. Write the expression ||u|| ||v|| w in standard form.

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Your solution:

||4i - 3j||. sqrt( 4^2 + 3^2) = 5.

||-3i + 4j|| = 5.

25* (6i - 3j)

150 i - 75j.

confidence rating #$&*:

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Given Solution:

|| u || = sqrt( 4^2 + 3^2) = 5

and

|| v || = sqrt(3^2 + 4^2) = 5

so that

|| u || || v || w = 5 * 5 * w = 25 * (6 i - 3 j ) = 150 i - 75 j.

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Self-critique (if necessary): OK

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Self-critique rating: OK

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Question: Let u = 4i + j, v = 4i + 3j, w = -i + 2j. Find a vector of length 3 with the same direction as u - 2v + 2w.

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Your solution:

u = 4i + j

-2v= -2(4i + 3j) = -8i -6j.

2w = 2*(-i + 2j) = -2i +4j.

u - 2v + 2w = -6i -j.

3*(-6i -j)/||-6i -j||.

-18/sqrt(37) i -3/sqrt(37) j.

confidence rating #$&*:

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Given Solution:

u - 2v + 2w = -6 i - j

so

|| u - 2 v + 2 w || = sqrt(37)

and

( u - 2 v + 2 w ) / || u - 2 v + 2 w || = -6 sqrt(37) / 37 i - sqrt(37) / 37 j

is a unit vector in the directio of u - 2 v + 2 w .

A vector of magnitude 3 in this direction is therefore

3 ( -6 sqrt(37) / 37 * i - sqrt(37) / 37 * j ) =

-18 sqrt(37) / 37 i - 3 sqrt(37) / 37 j

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Self-critique (if necessary): OK

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Self-critique rating: OK

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Question: Show that the vector v = cos(theta)i + sin(theta)j is a unit vector for any angle theta.

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Your solution:

Magnitude of this is sqrt of the components squared which is always 1 in the case of sin and cos theta. Thus always a unit vector.

confidence rating #$&*:

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Given Solution: || v || = sqrt( cos^2(theta) + sin^2(theta) ) = sqrt(1) = 1.

A vector of magnitude 1 is a unit vector.

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Self-critique (if necessary): OK

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Self-critique rating: OK

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Self-critique (if necessary):

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Self-critique rating:

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&#Very good work. Let me know if you have questions. &#