12-01-11

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course Phy 202

11:30pm Jan 20, 2012This is only part of the assignment. I just checked my e-mail today.. I was expecting this to be due Sunday night. Oh well, I'll have the rest done and turned in tomorrow.

Physics II Class 120111

(This document contains class notes of 1/09/12 and 1/11/12. It is duplicated under the date 120111).

Your best attempt on the questions posed here will be due by the end of the day on Friday, 1/20/12.

To raise a vertical water column 10 cm requires about an additional 1.0% of atmospheric pressure.

To achieve a 1% increase in the pressure of a confined gas at constant volume requires that its absolute temperature be raised 1%.

If the absolute temperature of a confined gas increases by 1% without changing its pressure, its volume increases by 1%.

For our purposes the freezing and boiling points of water at atmospheric pressure are defined, respectively, to be 0 Celsius and 100 Celsius. This is not the standard SI definition. You are not yet expected to be prepared to understand the standard SI unit, so for the moment we are using the ‘old’ definition. The two definitions agree to about 5 significant figures.

A mole of ideal gas at atmospheric pressure at 0 Celsius occupies 22.4 liters; for ballpark calculations you could use either 20 or 25 liters as a basis for estimation.

To raise the temperature of a mole of a monatomic ideal gas by one degree Celsius requires about 21 Joules, provided the gas is allowed to expand at constant pressure. If the gas is confined to a constant volume then it doesn’t have to do the work of expansion, and requires only 3/5 as much energy. If the gas is diatomic then every degree of temperature increase requires about 8 Joules more than if it was monatomic (the extra energy is needed because diatomic molecules can and do spin as a result of their collisions with other molecules, which takes additional energy).

The change in the potential energy of an object or system (designated `dPE) between two events is defined to be equal and opposite to the work done by conservative forces on the system between those events. Examples of conservative forces are gravitational, electrostatic and magnetic forces, as well as ideal elastic forces.

The weight of an object is the force exerted on it by gravity. The force exerted on an object by gravity in the vicinity of the Earth’s surface will, in the absence of other forces, accelerate that object toward the center of the Earth at 9.8 meters / second^2, which is also equal to 980 centimeters / second^2 and close to 32 feet / second^2. We use g to stand for this acceleration. Since the unopposed gravitational force gives the object this acceleration, the gravitational force on the object must be F_grav = m g, where m is its mass. Thus the weight of an object of mass m, near the surface of the Earth, is weight = m g.

If we raise the object its displacement is in the direction opposite its displacement, so that the gravitational force does negative work on it.

The equation of motion of an object undergoing simple harmonic motion is x(t) = A cos(omega * t + theta_0), where omega is the angular frequency of the motion, A the amplitude and theta_0 the initial angular position of the circular-model reference point. In the absence of other information theta_0 may be taken to be zero. In SI units the angular frequency is equal to the frequency of the motion in cycles per second, multiplied by the 2 pi radians in a cycle.

In an elastic collision, kinetic energy is conserved. An object which collides elastically with a much more massive object loses negligible kinetic energy.

`q000. Report the data you obtained in lab on 1/09 and 1/11. Include a brief but clear description of what you did, and report the data in a concise, organized, self-explanatory table.

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JAN 9

System: Holding a wood-like strip at two points and ""shaking"" to measure the frequency (oscilation/sec)

Data: Horizonatal (w/ gravity)

Distance between end1 and hand1 (H1) --> 24.5cm

H1 and H2 --> 73cm

H2 and end2 --> 25.5cm

>>>22 osc in 7 sec

: Vertical (perpendicular to gravity)

Distance between end1 and hand1 (H1) --> 36.5cm

H1 and H2 --> 47.5cm

H2 and end2 --> 39cm

>>>12 osc in 2.3 sec

System: Balancing a wood-like strip on [a domino on a cd on a cup] at two seperate points and ""releasing weight"" to see how long it oscilates

Data: Distance between end1 and structure1 (S1) --> 24.5cm

S1 and S2 --> 73cm

S2 and end2 --> 25.5cm

>>>took 18.3 sec to stop

: Distance between end1 and structure1 (S1) --> 36.5cm

S1 and S2 --> 47.5cm

S2 and end2 --> 39cm

>>>took 20.4 sec to stop

JAN 11

System: Balancing a wood-like strip on 3 structures to try to create the longest lasting oscilation

Data: Distance between end1 and structure1 (S1) --> 52.5cm

S1 and S2 --> 92cm

S2 and S3 --> 71cm

S3 end3 -->28cm

>>> 43 sec

: Distance between end1 and structure1 (S1) --> 74cm

S1 and S2 --> 81.5cm

S2 and S3 -->79.5 cm

S3 and end3 --> 12cm

>>> 61 sec

: Distance between end1 and structure1 (S1) --> 17cm

S1 and S2 --> 69cm

S2 and S3 --> 135cm

S3 and end3 --> 24.5cm

>>> 16 sec

: Distance between end1 and structure1 (S1) --> 56.5cm

S1 and S2 --> 58.5cm

S2 and S3 --> 71.5cm

S3 and end3 --> 59cm

>>> 56 sec

: Distance between end1 and structure1 (S1) --> 17cm

S1 and S2 --> 115cm

S2 and S3 --> 102.5cm

S3 and end3 --> 11cm

>>> 36 sec

#$&* Please note the following: Your response to the question should be inserted in the ‘middle line’ which is the line following the **** and before the #$&*. Follow this practice throughout the course. Never add anything to or delete anything from any line that begins with #$&* or ****.

`q001. What would be the potential energy change of a 10 gram mass of water whose vertical position changes by 40 centimeters?

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PE - equal and opposit to the work done by the conservative force

looking for d'PE of 10g of water that lowers 40cm

if it's lowering then it's PE is decreasing as well

d'PE = - (row->desity) * (d'Volume) * (g->gravity) * (y->height of water)

= - (1 g *cm^3) * (mass/density) * (9.8 m/sec^2) * (40cm)

= - (1 g *cm^3) * (10g / 1g*cm^3) * (9.8 m/sec^2) * (40cm)

= - 392000g*cm^2/sec^2

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Right. Reasoning looks pretty much OK, but check out the following to be sure:

The weight of the water is the force exerted on it by gravity. A 10 gram mass of water has weight 10 grams * 980 cm/s^2 = 9800 g cm/s^2.

Thus gravity, a conservative force, exerts a downward force of 9800 g cm / s^2 as the vertical position of the water increases by 40 cm.

The magnitude of the work done is therefore 9800 g cm^ / s^2 * 40 cm = 392 000 g cm^2 / s^2.

The work done by gravity on the water is therefore the product of a downward force and an upward displacement, so the work is negative:

work done by gravity on water = - 392 000 g cm^2 / s^2.

The change in the water's PE is equal and opposite the work done by gravity, so

`dPE = +392 000 g cm^2 / s^2.

Notes on units:

9800 g cm / s^2 is 9800 dynes.

392 000 g cm^2 / s^2 is 392 000 ergs.

The calculations could have also been done in SI units:

.010 kg * 9.8 m/s^2 = .098 Newtons

.098 Newtons * 0.40 meters = .0392 Joules.

Symbolically:

The PE change of mass m of water changing vertical position by `dy is symbolically reasoned out by the following sequence of steps:

Weight of the mass m is weight = (m * g) = magnitude of downward force of gravity.

If upward is positive, then the force of gravity is negative, and the work done by gravity is

`dW_grav = (- m * g ) * `dy.

Change in PE is equal and opposite work done by conservative forces, so

`dPE = - ( -m * g) * `dy = m g `dy.

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`q002. If the potential energy of 10 grams of water, which we will consider to be initially at rest, changes by 100 000 g cm^2 / s^2 (which is equal to .01 kg m^2 / s^2 or .01 Joules),

and if this PE loss is converted to KE, then how fast is the water moving?

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PE of 10g of water changes by 100,000gcm^2/sec^2

PE is converted to KE

velocity of water?

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`q003. A stream of water spurts out of the side of a vertical cylinder, falling 60 centimeters while traveling 40 centimeters in the horizontal direction. Assuming that the horizontal velocity of the water remains constant, what was the speed of the water as it exited the cylinder?

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`q004. If the frequency of the oscillation of a strip of plastic between two dominoes separated by 40 cm is 5 cycles per second, with amplitude 2 cm, then assuming that each point on the strip undergoes SHM:

What is the equation of motion of the point halfway between the dominoes?

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Calculate or estimate the amplitude of motion for a point on the strip which is ¼ of the way between the dominoes.

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Based on your estimate what is the equation of motion of this point?

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What is the equation of motion of a point on the strip which is 1/6 of the way between the dominoes?

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If x is the coordinate of a point on the strip, as measured from the domino on the left, what is the equation of motion at this point?

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`q005. If a ball of mass 10 grams, moving at 500 cm / s in a direction perpendicular to a wall, strikes the wall and bounces off elastically, then what is its momentum change from the moment it contacts the wall until it comes to rest?

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What is its momentum change between the time it comes to rest and the time it loses contact with the wall?

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What is its momentum change between its first contact and its last contact with the wall?

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If the ball bounces elastically off of another wall and returns to the original wall every .1 second, what average force does it exert on that wall?

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In the above, be sure you have treated velocity as a vector quantity. Mainly this means that you need to declare a positive direction and abide by your declaration.

`q006. If the temperature of the air in a 2-liter bottle increases by 10 degrees Celsius, how much energy is required? Air consists of a mix of gases, most of which are diatomic.

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`q007. A plastic tube has inner diameter about 3 cm.

What is the volume inside a 10-cm length of this tube?

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What percent is this of the volume of a 500-milliliter bottle?

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How many 10-cm lengths of this tube would be required to match 1% of the volume of a 500-millileter bottle?

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If the air in a 500-milliliter bottle is heated until the water in the tube rises 10 cm, by what percent did the volume of the bottle increase, and by what percent do you think the temperature of the air had to increase?

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`q008. A plastic strip resting on a series of dominoes, including dominoes at its ends, is expected to resonate if the dominoes are equally spaced. What are the first five domino spacings expected to produce harmonic resonance in a strip of plastic 4 meters long?

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`q009. A certain aluminum rod is supported at the middle. When the end of the rod is struck sharply in a direction perpendicular to the rod, it produced a bell-like sound with a frequency of 300 cycles / second and amplitude .3 millimeters.

What is the maximum speed of the simple harmonic motion of a point on the end? (Note that you can determine this if you think about the SHM: what is the amplitude and frequency of the SHM of this point, and how do you use the amplitude and frequency of the SHM to find the maximum speed?)

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Data and the first question look good.

Check out my note and see what you can do with the rest of the questions.

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