course phy 121
The original quiz is in word format where I drew a graph using the draw functions of the program. when copying and pasting, I do not see the graph. I will email you with an attachment
I need your description of the graph, not the actual graph. It's usually quicker to hand-sketch a graph than to construct it using the computer, but either way it's the description that tells me what you understand.
If an object increases velocity at a uniform rate from 7 m/s to 21 m/s in 11 seconds, what is its acceleration and how far does it travel?Sketch a velocity vs. clock time graph for an object whose initial velocity is 7 m/s and whose velocity 11 seconds later is 21 m/s. Explain what the slope of the graph means and why, and also what the area means and why.
v0=7m/s, vf=21m/s, tf=11 sec
vAve=vf+v0/2. =21m/s + 7m/s / 2, =28m/s/2= 14m/s
'dv=vf-v0, 21m/s-7m/s=14msec
aAve='dv/'dt, =14m/sec/11sec, = 1.27m/s^2
'ds='dv*'dt, =14m/sec* 11s= 154m
On the graph of velocity vs. time where acceleration is uniform, v vs t is linear. The rise between two graph points is ?v where the run between two graph points is the ?t. As the velocity changes, its rate of change is represented by the slope; rise/run. The area under the line is the ?s or its position of change
This is exactly what I need to see. Good work.