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course Phy 241
7/15/2013 9:55 pm
An automobile traveling a straight line is at point A at clock time t = 4 sec, where it is traveling at 10 m/s, to point B at clock time t = 11 sec, where it is traveling at 20.5 m/s. Point A is 75 meters from the starting point and point B is 115 meters from the starting point. What are the average velocity and the average acceleration of the automobile during the specified time? What evidence is there that the acceleration is or is not uniform?At point A:
vAve = 75m/4s = 18.75m/s
aAve = 10m/s/4s = 2.5m/s^2
At point B:
vAve = 40m/7s ≈ 5.714m/s
aAve = 20.5m/s/7s ≈ 2.929m/s^2
The acceleration is not uniform because it is higher on the second interval than the first.
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There is only one interval for which you have sufficient information to find the average velocity and average acceleration.
You appear to have assumed that the position and velocity were both 0 at t = 0. This is not given and there is no reason to assume it.
All you know is what happened between t = 4 sec and t = 11 sec.
What do you get when you analyze this single interval?
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