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RESPONSE --> The magnitude of the force= Q is F = k q1 * Q / r^2. To find the direction of this displacement vector we find arctan(y / x), adding 180 deg if x is negative.
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15:11:38 ** The magnitude of the force on a test charge Q is F = k q1 * Q / r^2, where q1 is the charge at the origin. The force is one of repulsion if q1 and Q are of like sign, attraction if the signs are unlike.
The force is therefore directly away from the origin (if q1 and Q are of like sign) or directly toward the origin (if q1 and Q are of unlike sign). To find the direction of this displacement vector we find arctan(y / x), adding 180 deg if x is negative. If the q1 and Q are like charges then this is the direction of the field. If q1 and Q are unlike then the direction of the field is opposite this direction, 180 deg more or less than this direction. **......!!!!!!!!...................................
RESPONSE --> I understand that q1 is the charge at orgin. So if the force is directly away from the orgin q1 and Q are not like sign and if directly toward the orgin q1 and Q are unlike sign. When we find the direction of the displacement vector if q1 and Q are like charges then this is the direction of the field. If they are unlike then the direction of the field is opposite.
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15:15:00 Explain how we calculate the magnitude and direction of the electric field at a given point of the x-y plane point due to a given point charge at the origin.
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RESPONSE --> The electric field= F / Q = k q1 / r^2. The electric field is directly away from the origin if q1 is positive or toward the origin if q1 is negative. The direction of the electric field is in the direction of the displacement vector from the origin to the point if q1 is positive, and opposite to this direction if q1 is negative.
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15:17:00 ** The magnitude of the force on a test charge Q is F = k q1 * Q / r^2, where q1 is the charge at the origin.
The electric field is therefore F / Q = k q1 / r^2. The direction is the direction of the force experienced by a positive test charge. The electric field is therefore directly away from the origin (if q1 is positive) or directly toward the origin (if q1 is negative). The direction of the electric field is in the direction of the displacement vector from the origin to the point if q1 is positive, and opposite to this direction if q1 is negative. To find the direction of this displacement vector we find arctan(y / x), adding 180 deg if x is negative. If q1 is positive then this is the direction of the field. If q1 is negative then the direction of the field is opposite this direction, 180 deg more or less than this direction. **......!!!!!!!!...................................
RESPONSE --> Again I understand is q1 is positive then is is the direction of the field and if q1 is neg. the direction of the field is opposite this direction by 180 degrees more or less than this direction.
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