course Mth 158 ????}?K?n????????assignment #001
......!!!!!!!!...................................
22:00:54 query R.1.26 \ was R.1.14 (was R.1.6) Of the numbers in the set {-sqrt(2), pi + sqrt(2), 1 / 2 + 10.3} which are counting numbers, which are rational numbers, which are irrational numbers and which are real numbers?
......!!!!!!!!...................................
RESPONSE --> 1/2: rational number 10.3: counting number pi: irrational number sqrt(2): irrational number -sqrt(2): irrational number All are real numbers
.................................................
?????Z?_?w]??K?T?? assignment #001 001. `Query 1 College Algebra 05-29-2009 ?W???j???????assignment #001 001. `Query 1 College Algebra 05-29-2009
......!!!!!!!!...................................
22:04:57 ** Counting numbers are the numbers 1, 2, 3, .... . None of the given numbers are counting numbers Rational numbers are numbers which can be expressed as the ratio of two integers. 1/2+10.3 are rational numbers. Irrational numbers are numbers which can be expressed as the ratio of two integers. {-sqrt(2)}, pi+sqrt(2) are irrational numbers.. **
......!!!!!!!!...................................
RESPONSE --> 10.3 is not a counting numbers but rather a rational number.
.................................................
......!!!!!!!!...................................
22:05:34 query R.1.44 \ 32 (was R.1.24) Write in symbols: The product of 2 and x is the product of 4 and 6
......!!!!!!!!...................................
RESPONSE --> 2x = (4)*(6)
.................................................
......!!!!!!!!...................................
22:09:13 query R.1.62 \ 50 (was R.1.42) Explain how you evaluate the expression 2 - 5 * 4 - [ 6 * ( 3 - 4) ]
......!!!!!!!!...................................
RESPONSE --> always start with parenthesis so 3-4 is -1 then multiply by 6 is -6. multiplication is next so 5 * 4 is 20 then do subtraction which will be 2-20-(-6) = -12
.................................................
......!!!!!!!!...................................
22:13:30 query R.1.98 \ 80 (was R.1.72) Explain how you use the distributive property to remove the parentheses from the express (x-2)(x-4).
......!!!!!!!!...................................
RESPONSE --> (x-2)x + (x-2)2y so x^2-2x+2xy-4y
.................................................
......!!!!!!!!...................................
22:16:29 ** COMMON ERROR: Using FOIL. FOIL is not the Distributive Law. FOIL works for binomial expressions. FOIL follows from the distributive law but is of extremely limited usefulness and the instructor does not recommend relying on FOIL. Starting with (x-2)(x-4) ; one application of the Distributive Property gives you x(x-4) - 2(x-4) . Applying the property to both of the other terms we get x^2 - 4x - (2x -8). Simplifying: x^2 - 4x - 2x + 8 or x^2 - 6x + 8. *
......!!!!!!!!...................................
RESPONSE --> I used used and typed in the wrong numbers! but yes using FOIL. so again (x-4)x - (x-4)2 then multiply/simplify through x^2 - 4x - (2x -8) simplify again x^2 - 6x + 8
.................................................
......!!!!!!!!...................................
22:18:43 query R.1.102 \ 86 (was R.1.78) Explain why (4+3) / (2+5) is not equal to 4/2 + 3/5.
......!!!!!!!!...................................
RESPONSE --> because the numbers are in parenthesis and you always work parenthesis first. and you can not split up the numbers in the parenthesis in such a way
.................................................
......!!!!!!!!...................................
22:19:54 Query Add comments on any surprises or insights you experienced as a result of this assignment.
......!!!!!!!!...................................
RESPONSE --> I need to explain and show work properly in future assignments. I see what type of answers you are looking for.
.................................................
?????k??r??????assignment #001 001. `Query 1 College Algebra 05-29-2009