Assingment 29

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course PHY 232

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-

by-phrase interpretation of the problem along with a statement of what you do or do not

understand about it. This response should be given, based on the work you did in completing

the assignment, before you look at the given solution.

029. `Query 29

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Question: `qQuery introductory problem set 54 #'s 8-13

Explain how to determine the magnetic flux of a uniform magnetic field through a plane loop of

wire, and explain how the direction of the field and the direction of a line perpendicular to

the plane of the region affect the result.

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Your Solution:

Basically we find the area of the plane loop of wire, if given the radius find the area using

(pi*r^2) then multiply the area of the loop by the strength of the field.

Hence, we get the strength of the flux and if perpendicular to the loop then its at a non zero

angle with the field, then we mutiply the previous reasult by cosine of the angle.

confidence rating #$&*:

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Given Solution:

To do this we need to simply find the area of the plane loop of wire. If we are given the

radius we can find the area using

Pi * r ^2

Then we multiply the area of the loop (In square meters ) by the strength of the field (in

tesla).

This will give us the strength of the flux if the plane of the loop is perpendicular to the

field. If the perpendicular to the loop is at some nonzero angle with the field, then we

multiply the previous result by the cosine of the angle.

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Self-critique (if necessary):

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Self-critique Rating:ok

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Question: `qExplain how to determine the average rate of change of magnetic flux due to a

uniform magnetic field through a plane loop of wire, as the loop is rotated in a given time

interval from an orientation perpendicular to the magnetic field to an orientation parallel to

the magnetic field.

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Your Solution:

First of all we get the area of the loop and then multiply the area of the loop m^2 by the

strength of the field to find the flux when its perpendicular. As for the parallel use the

same procedure which we end up with flux 1 and 2 which if subtracted and divided by time gives

us the average rate of change if magnetic flux

confidence rating #$&*:

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Given Solution:

** EXPLANATION BY STUDENT:

The first thing that we need to do is again use Pi * r ^ 2 to find the area of the loop. Then

we multiply the area of the loop (m^2) by the strength of the field (testla) to find the flux

when the loop is perpendicular to the field.

Then we do the same thing for when the loop is parallel to the field, and since the cos of

zero degrees is zero, the flux when the loop is parallel to the field is zero. This makes

sense because at this orientation the loop will pick up none of the magnetic field.

So now we have Flux 1 and Flux 2 being when the loop is perpendicular and parallel,

respectively. So if we subtract Flux 2 from flux 1 and divide this value by the given time in

seconds, we will have the average rate of change of magnetic flux. If we use MKS units this

value will be in Tesla m^2 / sec = volts. **

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Self-critique (if necessary):

Alittle different approach but same idea.

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Self-critique Rating:ok

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Question: `qExplain how alternating current is produced by rotating a coil of wire with

respect to a uniform magnetic field.

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Your Solution:

When you rotate a coil of wire end over end inside a uniform magnetic field. When the coil is

parallel to the magnetic field, then there is no magnetic flux, and the current will be zero.

But then when the coil is perpendicular to the field or at 90 degrees to the field then the

flux will be strongest and the current will be moving in one direction. Then when the coil is

parallel again at 180 degrees then the flux and the current will be zero. Then when the coil

is perpendicular again at 270 degrees, then the flux will be at its strongest again but it

will be in the opposite direction as when the coil was at 90 degrees. So therefore at 90

degrees the current will be moving in one direction and at 270 degrees the current will be

moving with the same magnitude but in the opposite direction.

Which can be summed up as the changing of magnetic flux produces voltage which in turn

produces current

confidence rating #$&*:

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Given Solution:

** STUDENT RESPONSE WITH INSTRUCTOR COMMENT: Y

ou rotate a coil of wire end over end inside a uniform magnetic field. When the coil is