Phy 121
Your 'cq_1_8.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed upward at 15 meters / second from a height of 12 meters above the ground. Assume a uniform downward acceleration of 10 m/s^2 (an approximation within 2% of the 9.8 m/s^2 acceleration of gravity).
• How high does it rise and how long does it take to get to its highest point?
• - It rises 11.25 more and it takes 1.5 seconds.
• How fast is it then going when it hits the ground, and how long after the initial toss does it first strike the ground?
• - 21.6 m/s and it takes 2.16 seconds.
2.16 sec might be correct from the highest point, but not from the initial toss
• At what clock time(s) will the speed of the ball be 5 meters / second?
• - 1 second
• At what clock time(s) will the ball be 20 meters above the ground?
• This is not possible because the initial height is 12 and 20-12=18. The max height above the initial is 11.25 before turning and falling back to the ground.
• How high will it be at the end of the sixth second?
answer/question/discussion: It will be on the ground
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About 30 minutes.
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&#Good work. See my notes and let me know if you have questions. &#