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Phy 201
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
We first need to see how much the velocity increases in the 3 seconds. We would do this by multiplying the 8cm/s/s by 3 seconds. This gives us 24cm/s. We would then add this to the initial velocity and get 36 cm/s.
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
The average velocity is determined by adding the initial velocity to the final velocity and dividing by 2. 12cm/s+24cm/s=(36cm/s)/2=18cm/s.
24 cm/s is not the final velocity
if velocity goes from 12 cm/s to 36 cm/s the average is not 18 cm/s
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
We determine the displacement by taking the average velocity of 18cm/s and multiplying it by the number of seconds in the interval which is 3 seconds. We then find that the object travels 54 cm during this interval.
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8 minutes
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No need to resubmit as long as you understand your error in finding the average velocity.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
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