cq_1_101

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Phy 201

Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.

• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?

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answer/question/discussion: ->->->->->->->->->->->-> :

In an oscillation there are 4 amplitudes. Therefore 2/4 would be .5 or 30 seconds each. It would then take 1 second to get from one extreme point to the other and 30 seconds to get from the extreme point to equilibrium and 1 min 30 seconds to go from one extreme point to equilibrium to opposite extreme point and back to equilibrium

• What reasonable assumption did you make to arrive at your answers?

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answer/question/discussion: ->->->->->->->->->->->-> :

I did not have any information on the length of the pendulum so I just divided how long it took the whole oscillation by the number of amplitudes to arrive at the answer.

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8 minutes

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Good. You would call each of those phases a quarter-cycle.

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