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Phy 201
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
We need to use the formula: m1v1+m2v2= m1’v1’+m2’v2’
60g(80cm/s)+ 20g(0)= 60g(50cm/s)+ 20g(70cm/s)
4800+0=4400
No, the momentum is not the same.
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
The momentum of the marble would have to be 90cm/s to equal the momentum.
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10 minutes
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Very good.