Phy 121
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
->->->->->->->->->->->-> answer/question/discussion: (8sec, 28 cm/s)
• What is the velocity at the midpoint of this interval?
->->->->->->->->->->->-> answer/question/discussion: 28cm/s
• How far do you think the object travels during this interval?
->->->->->->->->->->->-> answer/question/discussion: 244cm, I think that I can multiply the average velocity by the time interval to get a distance.
• By how much does the clock time change during this interval?
->->->->->->->->->->->-> answer/question/discussion: 8 seconds.
• By how much does velocity change during this interval?
->->->->->->->->->->->-> answer/question/discussion: 24cm/sec
• What is the average rate of change of velocity with respect to clock time on this interval?
->->->->->->->->->->->-> answer/question/discussion: 3scm/sec
• What is the rise of the graph between these points?
->->->->->->->->->->->-> answer/question/discussion: 24
• What is the run of the graph between these points?
->->->->->->->->->->->-> answer/question/discussion: 8
• What is the slope of the graph between these points?
->->->->->->->->->->->-> answer/question/discussion: 3
• What does the slope of the graph tell you about the motion of the object during this interval?
->->->->->->->->->->->-> answer/question/discussion: Its velocity is increasing at 3cm/s/s
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
->->->->->->->->->->->-> answer/question/discussion: 3cm/s, I am unsure how to find this and am not totally confident in my answer.
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~25minutes
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&#Your work looks very good. Let me know if you have any questions. &#