#$&*
Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
F1 = -9.8 m/s^2 upward
F2 = 9.8 m/s^2 downward
F1 = 5 * -9.8 m/s^2
F2 = 6 * 9.8 m/s^2
F1 = -5 * 9.8 m/s^2 = -49 Newtons
F2 = 6 * 9.8 m/s^2 = 58.8 Newtons
W2 + (-T) – W1 + (-T)
Fnet = F2 – F1
58.8 – 49 = or = 11A = 9.8 Force Net
A = 9.8 / 11 = 0.9 m/s^2
Upward direction at 5 kg, Downward direction at 6 kg
A
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 1.8 m/s
v01 = -1.8 m/s
v(t) = v01 + at
a = 0.9, t = 1
v(t) = -0.9 m/s = velocity in one second
downward
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
As initial velocity of the system is with 5 down and 6 up, velocity is -0.9 that would be acceleration, not velocity
, still downward, but with less speed, the system is slowing down eventually moving in the other direction.
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1.5 hours
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10/4 5 pm
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Solution
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