cq_1_242

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Phy 201

Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Copy the problem below into a text editor or word processor.

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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.

• Is the total momentum of the system after collision the same as the total momentum before?

answer/question/discussion: ->->->->->->->->->->->-> :

No, the momentum of the system is not conserved in this case.

60 g * 80 cm/s + 20 g * 0 cm/s = 60 g * 50 cm/s + 20 g * 70 cm/s

4800 g cm/s = 4400 g cm/s

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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?

answer/question/discussion: ->->->->->->->->->->->-> :

v’b = 60 g * 80 cm/s – 60 g * 50 cm/s / 20 g

v’b = 90 cm/s

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25 minutes

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10/4 10:30 am EST

&#Very good responses. Let me know if you have questions. &#