cq_1_271

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Phy 201

Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.

• What is the weight of the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

400 g/1000 = 0.4 kg

w = mg

= 0.4 kg * 9.8 m/s^2

= 3.92 kg

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• What is the buoyant force on the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

T = Fb – mg

The sum of the forces is zero so

T + F_b - m g = 0.

Your equation sets the tension equal to the force to which it is actually equal and opposite.

2.5 N = Fb – 3.92 kg

Fb = 2.5 N + 3.92 kg

Fb = 6.42 Newtons

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• What therefore must be its volume?

P = 1000 kg/m^2

Fb = pvg

V = Fb/pg

V = 6.42 N / 1000 kg/m^2 * 9.8 m/s^2

V = 0.66 * 10^-3 m^3

= 0.66 ml

answer/question/discussion: ->->->->->->->->->->->-> :

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• What is its density?

answer/question/discussion: ->->->->->->->->->->->-> :

1000 kg/m^3

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45 minutes

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11/11 9:30 am EST

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