course PHY 121 7/5/2009 2:08 pm An automobile traveling a straight line is at point A at clock time t = 4 sec, where it is traveling at 10 m/s, to point B at clock time t = 11 sec, where it is traveling at 20.5 m/s. Point A is 75 meters from the starting point and point B is 115 meters from the starting point. What are the average velocity and the average acceleration of the automobile during the specified time? What evidence is there that the acceleration is or is not uniform? vAve = ‘ds / ‘dt ‘ds = 115 m – 75 m = 40 m ‘dt = 11 s – 4 s = 7 s vAve = 40 m / 7 s = 5.7 m/s aAve = ‘dv / ‘dt ‘dv = 20.5 m/s – 10 m/s = 10.5 m/s ‘dt = 11 s – 4 s = 7 s aAve = 10.5 m/s / 7 s = 1.5 m/s^2 vAve = (vf + v0)/2 vAve = (20.5 + 10) / 2 vAve = 30.5 / 2 vAve = 15.25 Since these does not equal vAve from earlier in the answer, this would be evidence that there in no uniformity.