Open Query 16

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course Phy 122

016. `Query 14*********************************************

Question: `qquery Principles of Physics and General College Physics 12.40: Beat frequency at 262 and 277 Hz; beat frequency two octaves lower.

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Your solution:

Beat frequency= 277Hz-262Hz=15Hz*(1/4)=3.75Hz

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Given Solution:

`aThe beat frequency is the difference in the frequencies, in this case 277 Hz - 262 Hz = 15 Hz.

One ocatave reduces frequency by half, so two octaves lower would give frequencies 1/4 as great. The difference in the frequencies would therefore also be 1/4 as great, resulting in a beat frequency of 1/4 * 15 Hz = 3.75 Hz.

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