Open Query 31

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course Phy 122

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Question: `qQuery Principles and General Physics 21.04. A circular loop of diameter 9.6 cm in a 1.10 T field perpendicular to the plane of the loop; loop is removed in .15 s. What is the induced EMF?

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Your Solution:

EMF= (1.1*(pi*.048^2))/.15=.053V

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Given Solution:

The average induced emf is the average rate of change of the magnetic flux with respect to clock time. The initial magnetic flux through this loop is

flux = magnetic field * area = 1.10 T * (pi * .048 m)^2 = .00796 T m^2.

Flux is designated by the Greek letter phi.

The flux is reduced to 0 when the loop is removed from the field, so the change in flux has magnitude .0080 T m^2. The rate of change of flux is therefore

`d phi / `dt = .0080 T m^2 / (.15 sec) = .053 T m^2 / sec = .053 volts.

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&#Very good responses. Let me know if you have questions. &#