#$&*
course mth158
july 4
012. `* 12
* 1.4.12 (was 1.4.6). Explain how you found the real solutions of the equation (1-2x)^(1/3) - 1 = 0
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Your solution:
Since the equation is to the power 1/3 you square both sides in order to give yourself whole numbers
( (1-2x)^(1/3) - 1 = 0 )^2 = 1 - 2x - 1 = 0
you then have to add 1 to the side with 0
1-2x = 1 you then subtract 1
-2x = 0
since 0 divided by 2 = 0 then the answer is 0 when plugged back in 0 = 0
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@& Excellent explanation.
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