#$&*
course mth158
july 4
014. `* 14
*********************************************
Question: * 1.6.12 (was 1.6.6). Explain how you found the real solutions of the equation | 1 - 2 z | + 6 = 9.
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
With the absolute value lines you have to set your equation to both negative and positive to get your solution.
First we need to subtract 6 from the original equation so
| 1 - 2 z | = 3 then we set 1 - 2z to both 3 and -3
1-2z = 3 or 1 - 2z = -3
-2z = 2 -2z = - 4
z = - 1 z = 2
the solution set is (-1,2)
"
@& See my notes on the other queries you submitted today. It appears that you could proceed to testing, but without seeing entire documents I can't say this for sure.*@
#$&*
course mth158
july 4
014. `* 14
*********************************************
Question: * 1.6.12 (was 1.6.6). Explain how you found the real solutions of the equation | 1 - 2 z | + 6 = 9.
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
With the absolute value lines you have to set your equation to both negative and positive to get your solution.
First we need to subtract 6 from the original equation so
| 1 - 2 z | = 3 then we set 1 - 2z to both 3 and -3
1-2z = 3 or 1 - 2z = -3
-2z = 2 -2z = - 4
z = - 1 z = 2
the solution set is (-1,2)
"
@& See my notes on the other queries you submitted today. It appears that you could proceed to testing, but without seeing entire documents I can't say this for sure.*@