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course mth158

july 4

005. `* 4

* R.4.36 (was R.5.30). What is the single polynomial that is equal to 8 ( 4 x^3 - 3 x^2 - 1 ) - 6 ( 4 x^3 + 8 x - 2 )?

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Your solution:

First you must distribute the 8 and the -6 into the equation so

8 ( 4 x^3 - 3 x^2 - 1 ) - 6 ( 4 x^3 + 8 x - 2 ) becomes because you must also distribute the negative in the negative 6

32x^3 -24x^2 -8 - 24x^3 -48x +12= then you combine like terms

8x^3 -24x^2 -48x +4 is your final answer

Self-critique (if necessary):

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Self-critique rating:

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