course Phy231
2/19/10 10:15am
Over a period of 12 seconds, an object increases its velocity at a uniform rate from 6 m/s to 22 m/s What is its acceleration and how far does it travel?
Graph velocity vs. clock time for this object and explain what the slope of the graph means and why, and also what the area means and why.
22m/s - 6m/s= 14m/s 14m/s *12s= 168m
22m/s - 6m/s= 14m/s. What therefore do we call 14 m/s? It has units of velocity, but is it initial, final, average, or change in velocity?
14m/s *12s= 168m
What quantity does 14 m/s represent?
What quantity does 12 s represent?
What quantity does the product of these two quantities therefore represent?
Is this the quantity you are trying to find?
The area under the slope is the total distance the object has traveled.
Why would the area equal the total distance?
It's slope is increasing at and increasing rate.
This isn't so (the slope of the v vs. t graph increases at a constant rate, since velocity increases at a constant rate; the slope of a position vs. t graph would increase at an increasing rate), but the question is what the slope means and why.
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