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course Phy 121
An automobile traveling a straight line is at point A at clock time t = 4 sec, where it is traveling at 10 m/s, to point B at clock time t = 11 sec, where it is traveling at 20.5 m/s. Point A is 75 meters from the starting point and point B is 115 meters from the starting point. What are the average velocity and the average acceleration of the automobile during the specified time? What evidence is there that the acceleration is or is not uniform?
vAve = 75m / 4sec = 18.75m/s point A
vAve = 115m / 11s = 10.5m/s point B
aAve = 10m/s / 4s = 2.5m/s^s point A
aAve = 20.5m/s / 11s = 1.86m/s^2
The car takes almost 3 times the amount of time to just over double its speed, so rise and run would be different resulting in a 2/3 pattern for the slope. "
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You aren't told where the car is or what it's doing at t = 0, so you can't assume it's at the starting point when t = 0.
The only information you really have applies to the interval between point A and point B.
See what you can conclude based on just that information.
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