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Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m * a
= 6kg * 9.8m/s^2 = 58.8 Newtons (heavier end)
=5kg * 9.8m/s^2 = -49 Newtons (lite end)
Fnet = 58.8 Newtons - 49 Newtons = 9.8 Newtons
a = Fnet / m = 9.8 Newtons / 11kg = +0.89m/s^2 (downward heavier mass)
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = -1.8m/s
`dt = 1s
`dv = vf - v0, vf = `dv + v0 = 0.89m/s - 1.8m/s = -0.91m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
The acceleration is positive because it is derived by the Fnet and m of the system initially. The velocity is negative because it's direction is opposite that of the positive direction, so this system is slowing down.
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&#Very good responses. Let me know if you have questions. &#