course mth 173
depth change between clock time t = 6.7 and clock time t = 13.4?......... plug t=6.7 into the function to get y = 53.55, then plug t = 13.4 into the function and get 48.608. then to find the rate of change divide the change in depth, y, by change in time, t. Then the rate of change is -.737. What is the rate of depth change at the clock time halfway between t = 6.7 and t = 13.4? ……… halfway between t = 6.7, and t = 13.4 is 10.05. plug 10.05 into the equation and you get 50.763 for the depth, then the rate of change from t = 6.7 and t = 10.05 is -1.202.
&#y(t) is the depth function. The rate of depth change function is y '(t), not y(t). The rate function can also be called r(t).
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&#The depth function is of the form y = a t^2 + b t + c. The rate function is therefore y ' (t) = 2 a t + b.
Can you correct your rate function and modify your results? &#
You have to plug the halfway clock time into the rate-of-change function. What is the rate-of-depth-change function for this depth function?
If the function y = .028 t2 + -1.3 t + 61 represents depth y vs. clock time t, then what is the average rate ofWhat function represents the rate r of depth change at clock time t? …..r =∆y / ∆t. What is the clock time halfway between t = 6.7 and t = 13.4, and what is the rate of depth change at this instant?.......the clock time halfway between t = 6.7 and t = 13.4 is 10.05. the rate of depth change at this instant is -1.202.
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If the function r(t) = .289 t + -2.7 represents the rate at which depth is changing at clock time t, then how much depth change will there be between clock times t = 6.7 and t = 13.4? …. Plug t = 6.7 into the rate equation and you get the rate which is 4.636, then you plug in the rate and time into the rate function r = ∆d/∆t and get d = 31.06 then repeat steps with t = 13.4 and get d = 44.036. Then subtract 31.06 from 44.036 and get the change in depth of 2.97.
• What function represents the depth?...... y = at^2 + bt + c
• What would this function be if it was known that at clock time t = 0 the depth is 200 ?..... y = 200
&#The rate function is of the form y = m t + b, so the depth function will be a quadratic function y = .5 m t^2 + b t + c, where c can be any number that fits the problem.
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&#Please respond with a copy of this document, including my comments. Insert your revisions and/or questions and mark them with &#&#. &#