course Mth 173 The Celsius temperature of a hot potato placed in a room is given by the function T = 41* 2- .0083 t + 17 , where t is clock time in seconds and T is temperature in Celsius. At what average rate is the temperature of the potato changing between clock times t = 15 and t = 15.1 seconds seconds? the temperature at t = 15 is 611.47 when it is plugged in to equation and the temp at t = 15.1 is 615.55 so therefore the average = change in temp/ change in clock time and the average time is 40.8C/s At what average rate is the temperature of the potato changing between clock times t = 15 and t = 15.01 seconds? average time is 41 C/s At what average rate is the temperature of the potato changing between clock times t = 15 and t = 15.001 seconds? average time is 40 C/s What do you estimate is the rate at which temperature is changing at clock time t = 15 seconds? when t=15 is plugged into the equation the temp is 611.47 The rate at which the Celsius temperature of a hot potato placed in a room is given by Rate = .049 * 2- .0083 t, where R is rate of change in Celsius degrees per second and t is clock time in seconds. How much temperature change do you estimate would occur between t = 15 and t = 30 seconds? -2.46 * (10 x -4) "