Assignment 21 Query

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course Phy 122

3/25 10 am

021. `Query 19

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Question: `qPrinciples of Physics and General College Physics Problem 24.54: What is Brewster's angle for an air-glass interface (n = 1.52 for glass)?

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Your solution:

tan(angle) = n glass

tan(angle) = 1.52

Therefore angle = tan^-1(1.52) = 56.7 degrees

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Given Solution:

`aBrewster's angle is the smallest angle theta_p of incidence at which light is completely polarized. This occurs when tan(theta_p) = n2 / n1, where n2 is the index of refraction on the 'other side' of the interface.

For an air-glass interface, n1 = 1 so tan( theta_p) = n2 / 1 = n2, the index of refraction of the glass. We get

tan(theta_p) = 1.52 so that

theta_p = arcTan(1.52). This is calculated as the inverse tangent of 1.52, using the 2d function-tan combination on a calculator. WE obtain

theta_p = 56.7 degrees, approximately.

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