course PHY202
Here are my results from the experiment on Friday. I am getting a negative number under the square root, let me know what I am missing there. Then I will find the velocity. Since we did not do all four experiments, we dont have tlong but we have tshort, so do we need to figure out tlong using the longest tube we used? Thanks,
You did well on these questions.
Let me know if you have specific questions.
Here are my results from the experiment on Friday. I am getting a negative number under the square root, let me know what I am missing there. Then I will find the velocity. Since we did not do all four experiments, we dont have tlong but we have tshort, so do we need to figure out tlong using the longest tube we used? Thanks,"
For 1.3
clock time depth
0 22.2
1.5 20.4
3.4 18.5
5.3 16.7
7.2 14.9
9.3 13
11.7 11.1
14.1 9.3
16.8 7.3
20.1 5.4
24.7 3.5
31.9 1.5
For 12 cm tube
0 22.2
2.3 20.4
5 18.5
7.8 16.7
10.4 14.9
13.7 13
17 11.1
20.9 9.3
25.2 7.3
30.4 5.4
37 3.5
47.8 1.5
y=.0151x^2 - 1.1325x + 22.194 for 1.3 cm tube
t = (--1.1325)+- sqrt(-1.1325)^2 - 4(.0151)(22.194-5) / (2*.0151) = negative number
(-1.1325)^2 - 4(.0151)(22.194-5) is about .24 and is positive. You get solutions about 54 and 21 seconds, only one of which corresponds to the time range of the experiment.
However it's the 'long-tube' setup that is to reach the 5 cm mark.
I've posted another more detailed note on this situation to the Phy 202 access site (19-19-125). See that note for even more detail.
v2=2(.0151)(t)+-1.1325)
y=.0069x^2 - .7628x + 22.152 for 12 cm tube
t=(--.7628) +- sqrt(-.7628)^2 - 4(.0069)(22.152-5) / 2*.0069 = negative number
v2= 2*.0069*t + -.7628
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