course Mth 151 July 15, 7:58 If your solution to stated problem does not match the given solution, you should self-critique per instructions athttp://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm
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Given Solution: 836 means 8 * 100 + 3 * 10 + 6 * 1, or 8 * 10^2 + 3 * 10^1 + 6 * 10^0. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): Self-critique Rating:3 ********************************************* Question: `q002. How would we write 34,907 in terms of powers of 10? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 3*10000+4*1000+9*100+0*10+7*1 3*10^47+4*10^3+9*10^2+7*10^0 Confidence rating: Ok ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 34,907 means 3 * 10,000 + 4 * 1000 + 9 * 100 + 0 * 10 + 7 * 1, or 3 * 10^4 + 4 * 10^3 + 9 * 10^2 + 0 * 10 + 7 * 1. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): Self-critique Rating:3 ********************************************* Question: `q003. How would we write .00326 in terms of powers of 10? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 0*.1+0*.01+3*.001+2*.0001+6*.00001= 0*10^-1+0*10^-2+3*10^-3+2*10^-4+6*10^-5 Confidence rating: Ok ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: First we note that .1 = 1/10 = 1/10^1 = 10^-1, .01 = 1/100 = 1/10^2 = 10^-2, .001 = 1/1000 = 1/10^3 = 10^-3, etc.. Thus .00326 means 0 * .1 + 0 * .01 + 3 * .001 + 2 * .0001 + 6 * .00001 = 0 * 10^-1 + 0 * 10^-2 + 3 * 10^-3 + 2 * 10^-4 + 6 * 10^-5 . &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): Self-critique Rating:3 ********************************************* Question: `q004. How would we add 3 * 10^2 + 5 * 10^1 + 7 * 10^0 to 5 * 10^2 + 4 * 10^1 + 2 * 10^0? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 300+50+7=357 500+40+2=542 357+542=899 Confidence rating: Ok ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: We would write the sum as (3 * 10^2 + 5 * 10^1 + 7 * 10^0) + (5 * 10^2 + 4 * 10^1 + 2 * 10^0) , which we would then rearrange as (3 * 10^2 + 5 * 10^2) + ( 5 * 10^1 + 4 * 10^1) + ( 7 * 10^0 + 2 * 10^0), which gives us 8 * 10^2 + 9 * 10^1 + 9 * 10^0. This result would then be written as 899. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):
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Given Solution: We would write the sum as (4 * 10^2 + 7 * 10^1 + 8 * 10^0) + (5 * 10^2 + 6 * 10^1 + 4 * 10^0) , which we would then rearrange as (4 * 10^2 + 5 * 10^2) + ( 7 * 10^1 + 6 * 10^1) + ( 8 * 10^0 + 4 * 10^0), which gives us 9 * 10^2 + 13 * 10^1 + 12 * 10^0. Since 12 * 10^0 = (2 + 10 ) * 10^0 = 2 * 10^0 + 10^1, we have 9 * 10^2 + 13 * 10^1 + 1 * 10^1 + 2 * 10^0 = 9 * 10^2 + 14 * 10^1 + 2 * 10^0. Since 14 * 10^1 = 10 * 10^1 + 4 * 10^1 = 10^2 + 4 * 10^1, we have 9 * 10^2 + 1 * 10^2 + 4 * 10^1 + 2 * 10^0 = 10^10^2 + 4 * 10^1 + 2 * 10^0. Since 10*10^2 = 10^3, we rewrite this as 1 * 10^3 + 0 * 10^2 + 4 * 10^1 + 2 * 10^0. This number would be expressed as 1042. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): Self-critique Rating:3"