volumes

course Phy 201

9/23/09 at 12pm

qa_areas_units_2course Phy 201

cѽQˆª쏽assignment #002

002. Volumes

qa areas volumes misc

02-06-2009

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04:50:55

`q001. There are 9 questions and 4 summary questions in this assignment.

What is the volume of a rectangular solid whose dimensions are exactly 3 cm by 5 cm by 7 cm?

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RESPONSE -->

3cm*5cm*7cm=105cm^3

confidence rating: 1

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04:56:06

`q002. What is the volume of a rectangular solid whose base area is 48 square meters and whose altitude is 2 meters?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

V=A*h so V=48m^2*2m=96m^3

confidence rating: 3

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04:57:25

`q003. What is the volume of a uniform cylinder whose base area is 20 square meters and whose altitude is 40 meters?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

V=A*h so V=20m^2 *40m=800m^3

confidence rating: 3

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04:59:40

`q004. What is the volume of a uniform cylinder whose base has radius 5 cm and whose altitude is 30 cm?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

first you should square your radius so 5^2 is 25cm^2 then V=A*h so V=25cm^2*30cm=750cm^3

confidence rating: 2

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05:01:16

02-06-2009 05:01:16

The cylinder is uniform, which means that its cross-sectional area is constant. So the relationship V = A * h applies.

The cross-sectional area A is the area of a circle of radius 5 cm, so we see that A = pi r^2 = pi ( 5 cm)^2 = 25 pi cm^2.

Since the altitude is 30 cm the volume is therefore

V = A * h = 25 pi cm^2 * 30 cm = 750 pi cm^3.

Note that the common formula for the volume of a uniform cylinder is V = pi r^2 h. However this is just an instance of the formula V = A * h, since the cross-sectional area A of the uniform cylinder is pi r^2. Rather than having to carry around the formula V = pi r^2 h, it's more efficient to remember V = A * h and to apply the well-known formula A = pi r^2 for the area of a circle.

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NOTES -------> Always remember to use the entire formula in this case you left out the pi part of the area calculation.

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05:03:20

`q005. Estimate the dimensions of a metal can containing food. What is its volume, as indicated by your estimates?

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RESPONSE -->

V=A*h V=1in^2*4in= V=4in^3 I just made up the numbers.

confidence rating: 3

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05:05:12

`q006. What is the volume of a pyramid whose base area is 50 square cm and whose altitude is 60 cm?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

V=A*h V= 50cm^2*60cm=3000cm^3

confidence rating: 3

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05:07:08

02-06-2009 05:07:08

We can't use the V = A * h idea for a pyramid because the thing doesn't have a constant cross-sectional area--from base to apex the cross-sections get smaller and smaller. It turns out that there is a way to cut up and reassemble a pyramid to show that its volume is exactly 1/3 that of a rectangular solid with base area A and altitude h. Think of putting the pyramid in a box having the same altitude as the pyramid, with the base of the pyramid just covering the bottom of the box. The apex (the point) of the pyramid will just touch the top of the box. The pyramid occupies exactly 1/3 the volume of that box.

So the volume of the pyramid is V = 1/3 * A * h. The base area A is 30 cm^2 and the altitude is 60 cm so we have

V = 1/3 * 50 cm^2 * 60 cm = 1000 cm^3.

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NOTES -------> Volume of a pyrmid is 1/3 of a rectangular solid so V=1/3*A*h

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05:08:34

`q007. What is the volume of a cone whose base area is 20 square meters and whose altitude is 9 meters?

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RESPONSE -->

V=1/3*A*h=1/3*20m^2*9m=60m^3

confidence rating: 3

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05:12:22

`q008. What is a volume of a sphere whose radius is 4 meters?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

First start with A=pi *r^2 so A=3.14*16=50.24 Then use the formulaV=1/3*A*h so V=1/3*50.24m^2*8m=134m^3

confidence rating: 0

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05:13:54

02-06-2009 05:13:54

The volume of a sphere is V = 4/3 pi r^3, where r is the radius of the sphere. In this case r = 4 m so

V = 4/3 pi * (4 m)^3 = 4/3 pi * 4^3 m^3 = 256/3 pi m^3.

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NOTES -------> Just needed to know the formula for the sphere V=4/3 pi r^3

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05:15:48

`q009. What is the volume of a planet whose diameter is 14,000 km?

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RESPONSE -->

V=4/3*3.14*7000^3=1.436026667E12 km^3 according to my calculator.

confidence rating: 1

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05:17:31

`q010. Summary Question 1: What basic principle do we apply to find the volume of a uniform cylinder of known dimensions?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

Volume= Area * h where Area is the base and h is the altitude

confidence rating: 3

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05:18:05

`q011. Summary Question 2: What basic principle do we apply to find the volume of a pyramid or a cone?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

V=1/3 *A*h

confidence rating: 3

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05:18:29

`q012. Summary Question 3: What is the formula for the volume of a sphere?

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

V=4/3 pi r^3

confidence rating: 3

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05:19:18

`q013. Explain how you have organized your knowledge of the principles illustrated by the exercises in this assignment.

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

This assignment was helpful I have recorded all the notes for the formulas and hopefully can remember them all.

confidence rating: 3

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