course Phy 201 got a subscript error at about the 9th question. don't know if this is a program glitch. assignment #001001.
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01:59:01 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> the standard deviation is given by taking the square root of a squared average deviation of a set of numbers confidence assessment: 1
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02:02:10 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> fitting a best fit line requires trying to get the line as close to all of the points as possible. if two different people are doing the same experiment they may plot their version of the best fit line differently; the error lies in the human eye confidence assessment: 2
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02:04:21 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> velocity shows magnitude and direction of an object how fast an object is going and which way it's going confidence assessment: 3
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02:06:35 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> this gives the average velocity of an object: displacement / elapsed time self critique assessment: 2
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02:07:30 Given average speed and time interval how do you find distance moved?
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RESPONSE --> you multiply average speed and time interval together to get the distance confidence assessment: 2
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02:07:41 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> right self critique assessment: 3
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02:08:45 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> you divide distance by average speed confidence assessment: 2
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02:08:57 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> right self critique assessment: 3
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02:09:25 Given time interval and distance moved how do you get average speed?
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RESPONSE --> distance / time = average speed confidence assessment: 3
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02:09:38 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> right self critique assessment: 3"