Phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Answer the following based on Newton's Second Law:
*
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: F = 12 kg * 3 m/s^2 = 36 N
*
What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: a = F / m = (20 kg / m/s^2) / 4 kg = 5 m/s^2
*
If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: there are always other forces acting on objects, the normal force of gravity pulling down, friction in the opposite direction of movement, and the force that is applied by the person. There is almost always a little resistence against the initial force. 20 N + (10 kg * 1.5 m/s^2) = 35 N
*
What is the total of all those forces and in what direction does this total act?
answer/question/discussion: 35 N with movement, 98 N is the normal force of gravity pulling down on the object, Friction = 0. The forces act down and with the movement : 35 N + 98 N = 133 N
If a 10 kg object accelerates at 1.5 m/s^2, then the net force on the object is
F_net = m a = 10 kg * 1.5 m/s^2 = 15 kg m/s^2 = 15 N.
If your force was the only one acting on the object, then the net force on it would be 20 N and it would be accelerating at 2 m/s^2, not at 1.5 m/s^2.
If you are exerting a force of 20 Newtons on the object and the net force is only 15 Newtons, this means that the other forces acting on the object must total -5 Newtons. That s,there has to be a 5 N force opposing you.
** **
15 minutes
** **
&#Good work. See my notes and let me know if you have questions. &#