Phy 201
Your 'cq_1_16.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A rubber band has no tension until it reaches a length of 7.5 cm. Beyond that length its tension increases by .7 Newtons for every additional centimeter of length.
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What will be its tension if its endpoints are at the points (5 cm, 9 cm) and (10 cm, 17 cm) as measured on an x-y coordinate system?
answer/question/discussion: .1 m - .05 m = .05 m , .17 m - .09 m = .08 m , (.05 m , .08 m); sqrt(.05^2 + .08^2) = .09 m = 9 cm, 9 cm - 7.5 cm = 1.5 cm, 1.5 cm * .7 = 1.05 N
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What is the vector from the first point to the second?
answer/question/discussion: .1 m + .05 m = .15 m , .17 m + .09 m = .26 m ; (.15 m , .26 m)
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What is the magnitude of this vector?
answer/question/discussion: sqrt(.15^2 + .26^2) = .30 m
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What vector do you get when you divide this vector by its magnitude? (Specify the x and y components of the resulting vector).
answer/question/discussion: .15 m / .30 m = .5 , .26 m / .30 m = .87 ; (.5 , .87)
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What vector do you get when you multiply this new vector by the tension?
answer/question/discussion: .5 * 1.05 = .53 , .87 * 1.05 = .91 ; (.87 , .91)
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What are the x and y coordinates of the new vector?
answer/question/discussion: (.87 , .91)
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20 minutes
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Very good.